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Slav-nsk [51]
2 years ago
14

Hello people ~

Physics
2 answers:
slamgirl [31]2 years ago
8 0

Answer:

In case of electrostatic force, the work done is independent of path, it only depends on the final and initial positions of the charge. This path independent nature makes electrostatic force a conservative force. Thus, the option a becomes true, and the opposite statement (ie.

sleet_krkn [62]2 years ago
4 0

Answer:

Option A

Explanation:

As we know that electrostatic force is path independent

It is the force present between the charges of atoms .

Hence it's conservative force.

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The movement of continents changes wind patterns and ocean currents.

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Suppose your vehicle is moving 12m/s as it crosses the 7m line. It took 6 seconds to get to the 7m line. What was its accelerati
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3.61 m/s²

Explanation:

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The plate tectonic theory was initially rejected. TRUE. FALSE?
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A solenoid with 465 turns has a length of 8.00 cm and a cross-sectional area of 3.10 ✕ 10−9 m2. Find the solenoid's inductance a
hoa [83]

The solenoid's inductance and the average emf around the solenoid if the current changes from +3.50 A to −3.50 A in 7.83 ✕ 10−3 s will be 1.01 ×10⁻⁸ H and 9.02 × 10⁻² V.

<h3>What is a solenoid?</h3>

A coil of wire that carries an electric current is a solenoid. A solenoid is an electromagnet formed by a helical coil of wire.

Which generates a magnetic field when an electric current is passed through the coil.

A solenoid is a form of coil that produces a magnetic field when the electric current is passed through it. A solenoid is created when a conductive wire is used to make a loop.

Given data;

Turns ,N = 465

Length,L= 8.00 cm

Cross-sectional area,A = 3.10 ✕ 10−9 m2.

Solenoid's inductance, L=?

The average emf around the solenoid, E=?

Time of flow,t= 7.83 ✕ 10−3 s

Current changes from +3.50 A to −3.50 A

The inductance of the solenoid is found as;

\rm L =  \frac{\mu_0 AN^2}{L} \\\\ \rm L =  \frac{4 \times \pi \times 10^{-7}\times 3.0 \times 10^{-9} \times (465)^2 }{8.00 \times 10^{-2}} \\\\ L= 1.01 \times 10^{-8} \ H

The average emf around the solenoid is found as;

\rm e = L \frac{I_2-I_1}{t} \\\\ \rm e = 1.01 \times 10^{-8}  \times \frac{3.50-(-3.50)}{7.83 \times 10^{-3}} \\\\ e =9.02 \times 10^{-12} \  V

Hence, the solenoid's inductance will be 1.01× 10⁻⁸ H.

To learn more about the solenoid refer;

brainly.com/question/16015159

#SPJ1

3 0
2 years ago
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