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lorasvet [3.4K]
2 years ago
8

Antonia incorrectly solves the equation −2(14−54a)=6 . Her work is shown below.

Mathematics
1 answer:
bekas [8.4K]2 years ago
6 0

Answer:

For the yes/no bit:

step 1: no

step 2: no

step 3: yes

step 4: yes

step 5: no

for the final answer bit: a = 2  3/5 (the last option)

Step-by-step explanation:

yes/no bit:

step 1 is wrong because she didn't multiply -\frac{5}{4}a by -2

step 2 is wrong because she subtracted 1/2 instead of adding it

step 3 is correct because 6 - 1/2 = 11/2

step 4 is correct because she correctly multiplied both sides by 4

step 5 is wrong because she added 5 instead of dividing by -5.

for the final answer bit, I've attached an image below with my working out. hope this helps!

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Celeste uses 24 inches of ribbon from a spool that holds 36 inches of ribbon. Which shows equivalent representations for the par
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Ber [7]

The student with the correct answer is Dylan who says the decimal should be placed between the 8 and 0.

This is base on the estimation that 3.01 is a two decimal place number, so the product 18.06 should also be in 2 decimal place.

<h3>How to find product of decimal number?</h3>

A decimal number is a number expressed in the decimal system (base 10).

Place value:

  • Ten thousand
  • Thousand
  • Hundred
  • Ten
  • ones
  • . decimal point
  • tenth
  • hundredths
  • thousandth
  • ten thousandth
  • hundred thousandth

6 × 3.01

3.01

  • 3 = ones
  • . = decimal point
  • 0 = tenth
  • 1 = hundredth

6 × 3.01

= 18.06

Therefore, Lucas is incorrect with his answer that the decimal should be placed between the 1 and 8.

Read more on decimal number:

brainly.com/question/1827193

#SPJ1

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An aluminum recycling center pays0.08 per pound for cans how much will make receive for 21.5 pounds of cans
Neporo4naja [7]
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2 years ago
How many different 6- player starting squads can be formed from a volleyball team of 11 players?
aivan3 [116]
You have to calculate how many combinations of 6 people can be chosen from 11.   The formula for this is:
n! / [r! * (n-r)!]
combinations = 11! / [6! * 5!] =
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462 Combinations

Source:
http://www.1728.org/combinat.htm


7 0
2 years ago
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