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Gennadij [26K]
3 years ago
7

Finely ground nickel (II) hydroxide is placed in a beaker of water. It sinks to the bottom of the beaker and remains unchanged.

An aqueous solution of hydrochloric acid is then added to the beaker and the Ni(OH)2 disappears. Which reaction best describes what occurred in the beaker?
Your answer:

Ni(OH)2 (s) + HCl (aq) → NiO (aq) + H2 (g) + HCl (aq)

Ni(OH)2 (s) + 2 HCl (aq) → NiCl2 (aq) + 2 H2O (l)

Ni(OH)2 (s) + 2 H2O (l) → NiCl2 (aq) + 2 H2O (l)

Ni(OH)2 (s) + 2 H2O (l) → NiCl2 (aq) + 3 H2O (l) + O2 (g)
Chemistry
1 answer:
Luden [163]3 years ago
6 0

Explanation:

Acid-base reaction will give salt and water.

The 2nd option is correct.

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1. The solubility of AgNO3 at 20°C is 222.0g AgNO3/100g H2O. What mass of AgNO3 can be dissolved in 250 g of water at 20°C? Reca
neonofarm [45]

Answer :

(1) The mass of silver nitrate is, 555 g

(2) The solubility of the gas will be, 0.433 g/L

<u>Solution for Part 1 :</u>

From the given data we conclude that

In 100 gram of water, the amount of silver nitrate = 222 g

In 250 gram of water, the amount of silver nitrate = \frac{222}{100}\times 250=555g

Therefore, the mass of silver nitrate is, 555 g

<u>Solution for Part 2 :</u>

Formula used : S_1P_1=S_2P_2     (at constant temperature)

where,

S_1 = initial solubility of methane gas = 0.026 g/L

S_2 = final solubility of methane gas

P_1 = initial pressure of methane gas = 1 atm

P_2 = final pressure of methane gas = 0.06 atm

Now put all the given values in the above formula, we get the solubility of methane gas.

(0.026g/L)\times (1atm)=S_2\times (0.06atm)

S_2=0.433g/L

Therefore, the solubility of the gas will be, 0.433 g/L

5 0
3 years ago
In which way does a na1+ ion differ from a neutral na atom?
DochEvi [55]
Na 1+ misses 1 electron
8 0
3 years ago
Write the balanced equation for the ionization of the weak base pyridine, c5h5n , in water, h2o. Phases are optional.
Lelu [443]

The balanced equation for the ionization of the weak base pyridine,C5H5N in water, H2O

C_5H_5N ( aq.) + H2O ( l) ---------> C5H5NH+ (aq.) + OH- (aq.)

<h3>What is the balanced equation for the ionization?</h3>

Generally, Pyridine is characterized by a ring structure, in this characteristic ring structure N is sp2 hybridized, hence creating a lone pair present on N so s - character is more, as well as lone pair, is present.

Therefore, Considering The following functions of the equation:weak base pyridine,C5H5N in water, H2O

We write the balanced equation for the ionization as

C_5H_5N ( aq.) + H2O ( l) ---------> C5H5NH+ (aq.) + OH- (aq.)

Read more about  Chemical Reaction

brainly.com/question/11231920

6 0
2 years ago
Which shows the rational expression written using the least common denominator?
Alexandra [31]

Answer:

The first one.

\frac{x + 1}{4x^{2} } and \frac{4(x + 1)}{4x^{2} }

Explanation:

When comparing two fractions with variables like this, it's important to get to the same denominator in order to compare apples with apples and then be able to do not only comparisons but also perform additions/subtractions.

Question is which denominator to use and how to reach it.

In this case, the question and the answer choices do the work for you.  The question asks which one is the LEAST common denominator, and the answers show denominators x² and 4x².  The smallest of these is x², however, we can't simplify the first fraction to get to the x² denominator, so we'll go for the 4x².

So, the first fraction has already the correct denominator (4x²), we just have to transform the second one.

We multiply it by 1, expressed in a different way.  Since we're multiplying by one, we're not affecting the value, just the way it looks.

Let's do it!, to get the denominator to go from x² to 4x², we need to multiply it by 4... so we'll multiply by 4/4 (which is 1, neutral for the multiplication).

\frac{x + 1}{x^{2} } * \frac{4}{4} = \frac{4(x + 1)}{4x^{2} }

And now you have both fractions on the same denominator, without having changed their value, just their looks

6 0
3 years ago
Help plz..? this is really important to me and this is most of my grade may you please help?
Jet001 [13]
In sodium there are 11 electrons
In chlorine there are 17 electrons
There are 17 protons in chlorine
There are 11 protons in sodium

I’m not sure what an octet is I study in a British system if there’s anything else you’re not sure of search the Internet it has all the answers
3 0
3 years ago
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