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AnnyKZ [126]
3 years ago
13

Help Help Help Help Help Help Help Help Help Prove the divisibility of the following numbers: 10^9+10^8+10^7 by 555

Mathematics
1 answer:
raketka [301]3 years ago
4 0

10⁹ + 10⁸ + 10⁷ = 10⁷ (10² + 10¹ + 10⁰)

… = 10⁷ (100 + 10 + 1)

… = 10⁷ × 111

… = (2 × 5)⁷ × 111

… = 2⁷ × 5⁷ × 111

… = 2⁷ × 5⁶ × 555

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Answer:

Step-by-step explanation:

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4 years ago
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3 years ago
As part of quality-control program, 3 light bulbs from each bath of 100 are tested. In how many ways can this test batch be chos
hichkok12 [17]

Answer:

<h3>By 161700 ways this test batch can be chosen.</h3>

Step-by-step explanation:

We are given that total number of bulbs are = 100.

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Choosing 3 bulbs out of 100 don't need any specific order.

Therefore, applying combination formula for choosing 3 bulbs out of 100 bulbs.

^nCr = \frac{n!}{(n-r)!r!} read as r out of n.

Plugging n=100 and r=3 in above formula, we get

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=\frac{100\times 99\times 98\times 97!}{97!3!}

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= 161700 ways.

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