X - 11 / 3 = - 4 / 5 x + 5 / 6

Given a population with a mean of muμequals=100100 and a variance of sigma squaredσ2equals=3636, the central limit theorem appl

lakkis [162]

Answer:

a) $\bar X \sim N(100,\frac{6}{\sqrt{25}}=1.2)$

$\mu_{\bar X}=100$ $\sigma^2_{\bar X}=1$

b) $P(\bar X >101)=1-P(\bar X$

c) $P(\bar X$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

The complement rule is a theorem that provides a connection between the probability of an event and the probability of the complement of the event. Lat A the event of interest and A' the complement. The rule is defined by: $P(A)+P(A') =1$

Let X the random variable that represent the variable of interest on this case, and for this case we know the distribution for X is given by:

$X \sim N(\mu=100,\sigma=6)$

And let $\bar X$ represent the sample mean, by the central limit theorem, the distribution for the sample mean is given by:

$\bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}})$

a. What are the mean and variance of the sampling distribution for the sample means?

$\bar X \sim N(100,\frac{6}{\sqrt{25}}=1.2)$

$\mu_{\bar X}=100$ $\sigma^2_{\bar X}=1.2^2=1.44$

b. What is the probability that x overbarxgreater than>101

First we can to find the z score for the value of 101. And in order to do this we need to apply the formula for the z score given by:

$z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

If we apply this formula to our probability we got this:

$z=\frac{101-100}{\frac{6}{\sqrt{25}}}=0.833$

And we want to find this probability:

$P(\bar X >101)=1-P(\bar X$

On this last step we use the complement rule.

c. What is the probability that x bar 98less than

First we can to find the z score for the value of 98.

$z=\frac{98-100}{\frac{6}{\sqrt{25}}}=-1.67$

And we want to find this probability:

$P(\bar X$

5 0

3 years ago

On a 1‐mile walking tour of New York City, a group had to take a detour that was 300 yards shorter than half the distance of the

tresset_1 [31]

Answer:

580 yards long.

Step-by-step explanation:

The distance of the walking tour is = 1 mile

Step 1

We have to convert 1 mile to yards

Therefore ,

1 mile = 1760 yards

Step 2

We are told that the group took a detour that was 300 yards shorter than half the distance of the tour.

The second step would be to find out how many yards is equal to half the distance of the tour.

Half the distance of the tour = 1/2 of a mile

And in step 1 we have converted whole distance of the tour to yards

= 1 mile = 1760 yards.

Hence, Half the distance of the tour = 1760 yards ÷ 2

= 880 yards.

Step 3

The group took a detour that was 300 yards shorter than half the distance of the tour.

This means mathematically,

Half the distance of the tour - 300 yards

= 880 yards - 300 yards

= 580 yards.

Therefore, the detour was 580 yards long.

7 0

3 years ago

Maggie had 20 ribbons. 2/5 of the ribbons are polka-dot Ted ribbons. how many are not polka-dotted?

Solnce55 [7]

12 ribbons
p.s: im in 7th grade so you can trust me

5 0

3 years ago

Read 2 more answers

Burl and Paul paint signs together on a scaffold. Compared to their weights plus the weight of the scaffold, the sum of tensions

tatyana61 [14]

Answer:

equal

Step-by-step explanation:

If the scaffold is not accelerating either upward or downward, the sum of upward support forces is <em>the same as</em> the sum of downward weights being supported.

5 0

2 years ago

The histogram displays different numbers of days that customers rented a car. Which interval represents the most common number o

sleet_krkn [62]

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete, as the histogram is not attached.

However, the solution to your question is to select the interval with the highest frequency

Take for instance, after getting readings from the histogram, yiu have:

1 - 10: 8

11 - 20: 5

21 - 30: 11

31 - 40: 2

And so on.......

Interval 11 - 20 will represent the required interval because it has the highest frequency.

3 0

3 years ago