All categories

3 years ago

Analyze how elements and compounds in a balanced equation relate to the law of conservation of mass.

Chemistry

1 answer:

ICE Princess25 [194]3 years ago

5 0

Answer:

Balanced equation is related to the law of conservation of mass as it states that mass can neither be created nor be destroyed in a chemical reaction so the total no. of atoms in a reaction should remain same. in a balanced chemical equation also total no. of atoms of each elements remain same.

You might be interested in

The main constituent of gallstones is cholesterol. Cholesterol may have a role in heart attacks and blood clot formation. Its el

Nataly [62]

The main constituent of gallstones is cholesterol. Cholesterol may have a role in heart attacks and blood clot formation. Its elemental percentage composition is 83.87% C, 11.99% H, and 4.14% O. It has a molecular weight of 386.64 amu. Empirical formula is C₃H₄O₁ and Molecular formula is 7(C₃H₄O₁).

<h3>What is Empirical Formula ?</h3>

Empirical formula is the simplest whole number ratio of atoms present in given compound.

Element % Atomic mass Relative no. of atoms Simplest whole ratio

C 83.87 12 $\frac{83.87}{12}$ = 6.98 $\frac{6.98}{0.25}$ = 3

H 11.99 1 $\frac{11.99}{1}$ = 11.09 $\frac{11.09}{0.25}$ = 4

O 4.14 16 $\frac{4.14}{16}$ = 0.25 $\frac{0.25}{0.25}$ = 1

Thus the empirical formula is C₃H₄O₁.

<h3>How to find the Molecular formula of compound ?</h3>

Molecular formula = Empirical formula × n

n = $\frac{\text{Molecular weight}}{\text{Empirical formula weight}}$

= $\frac{386.64}{56}$

= 7

Molecular formula = Empirical formula × n

= 7 (C₃H₄O₁)

Thus from the above conclusion we can say that The main constituent of gallstones is cholesterol. Cholesterol may have a role in heart attacks and blood clot formation. Its elemental percentage composition is 83.87% C, 11.99% H, and 4.14% O. It has a molecular weight of 386.64 amu. Empirical formula is C₃H₄O₁ and Molecular formula is 7(C₃H₄O₁).

Learn more about the Empirical Formula here: brainly.com/question/1603500

#SPJ4

7 0

2 years ago

Please hurry and tell the answer to:

Flura [38]

Answer:

6.50 g of Hydrogen

Explanation:

We know that in every 20.0g of sucrose, there are 1.30g of hydrogen.

We now have 100.0g of sucrose. 100.0g is 5x larger than the 20.0g sample, which is a 5 : 1 ratio. Applying this ratio to the amount of hydrogen, we would have 5*1.3g of hydrogen in the 100.0g of sucrose.

5*1.3 = 6.5, so our answer is that there are 6.50g of hydrogen in 100.0g of sucrose.

Hope this helps!

5 0

1 year ago

How much heat energy is required to convert 48.3 g of solid ethanol at -114.5 degree C to gasesous ethanol at 135.3 degree C? Th

OLEGan [10]

Answer:

7.21 × 10⁴ J

Explanation:

Ethanol is solid below -114.5°c, liquid between -114.5°C and 78.4°C, and gaseous above 78.4°C.

<em>How much heat energy is required to convert 48.3 g of solid ethanol at -114.5°C to gaseous ethanol at 135.3 °C?</em>

<em />

We need to calculate the heat required in different stages and then add them.

The moles of ethanol are:

$48.3g.\frac{1mol}{46.07g} =1.05mol$

Solid-liquid transition

Q₁ = ΔHfus . n = (4.60 kJ/mol) . 1.05 mol = 4.83 kJ = 4.83 × 10³ J

where,

ΔHfus: molar heat of fusion

n: moles

Liquid: from -114.5°C to 78.4°C

Q₂ = c(l) . m . ΔT = (2.45 J/g.°C) . 48.3g . [78.4°C-(-114.5°C)] = 2.28 × 10⁴ J

where,

c(l): specific heat capacity of the liquid

ΔT: change in the temperature

Liquid-gas transition

Q₃ = ΔHvap . n = (38.56 kJ/mol) . 1.05 mol = 40.5 kJ = 40.5 × 10³ J

where,

ΔHvap: molar heat of vaporization

Gas: from 78.4°C to 135.3°C

Q₄ = c(g) . m . ΔT = (1.43 J/g.°C) . 48.3g . (135.3°C-78.4°C) = 3.93 × 10³ J

where

c(g): specific heat capacity of the gas

Total heat required

Q₁ + Q₂ + Q₃ + Q₄ = 4.83 × 10³ J + 2.28 × 10⁴ J + 40.5 × 10³ J + 3.93 × 10³ J = 7.21 × 10⁴ J

3 0

3 years ago

100 points to the person who can answer these 4 questions

Vinil7 [7]

Answer:

....,................................

Explanation:

1= A

2=D

3=C

4=C

8 0

3 years ago

What is the mass of 8.8 x 10^22 of magnesium

Romashka-Z-Leto [24]

Answer:

0.05

moles

Explanation:

In a mole of any substance, there exist

6.02⋅1023

units of that substance.

So here, we got:

3.01⋅1022Mg atoms⋅1mol6.02⋅1023M gatoms=0.05mol

3 0

3 years ago