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g100num [7]
3 years ago
8

A set of charged plates that have an area of 8.22*10^-4 m^2 and a separation of 2.42*10^-5 m have a potential difference of 25.0

V across them. How much charge is on the plates? (The answer is *10^-9 C. Just fill in the number, not the power.)​
Physics
2 answers:
faust18 [17]3 years ago
3 0

Answer: 7.51

Explanation: Acellus

GuDViN [60]3 years ago
3 0

Answer:

7.51

Explanation:

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A substance that Connor be broken down into simplersubstance by ordinary chemical means
Nana76 [90]

Answer:

An element

Explanation:

8 0
3 years ago
Sphere A with mass 80 kg is located at the origin of an xy coordinate system; sphere B with mass 60 kg is located at coordinates
IRINA_888 [86]

Answer:

Fc = [ - 4.45 * 10^-8 j ] N  

Explanation:

Given:-

- The masses and the position coordinates from ( 0 , 0 ) are:

       Sphere A : ma = 80 kg , ( 0 , 0 )

       Sphere B : ma = 60 kg , ( 0.25 , 0 )

       Sphere C : ma = 0.2 kg , ra = 0.2 m , rb = 0.15

- The gravitational constant G = 6.674×10−11 m3⋅kg−1⋅s−2

Find:-

what is the gravitational force on C due to A and B?

Solution:-

- The gravitational force between spheres is given by:

                       F = G*m1*m2 / r^2

Where, r : The distance between two bodies (sphere).

- The vector (rac and rbc) denote the position of sphere C from spheres A and B:-

 Determine the angle (α) between vectors rac and rab using cosine rule:

                   cos ( \alpha ) = \frac{rab^2 + rac^2 - rbc^2}{2*rab*rac} \\\\cos ( \alpha ) = \frac{0.25^2 + 0.2^2 - 0.15^2}{2*0.25*0.2}\\\\cos ( \alpha ) = 0.8\\\\\alpha = 36.87^{\circ \:}

 Determine the angle (β) between vectors rbc and rab using cosine rule:

                   cos ( \beta  ) = \frac{rab^2 + rbc^2 - rac^2}{2*rab*rbc} \\\\cos ( \beta  ) = \frac{0.25^2 + 0.15^2 - 0.2^2}{2*0.25*0.15}\\\\cos ( \beta  ) = 0.6\\\\\beta  = 53.13^{\circ \:}

- Now determine the scalar gravitational forces due to sphere A and B on C:

       Between sphere A and C:

                  Fac = G*ma*mc / rac^2

                  Fac = (6.674×10−11)*80*0.2 / 0.2^2  

                  Fac = 2.67*10^-8 N

                  vector Fac = Fac* [ - cos (α) i + - sin (α) j ]

                  vector Fac = 2.67*10^-8* [ - cos (36.87°) i + -sin (36.87°) j ]

                  vector Fac = [ - 2.136 i - 1.602 j ]*10^-8 N

       Between sphere B and C:

                  Fbc = G*mb*mc / rbc^2

                  Fbc = (6.674×10−11)*60*0.2 / 0.15^2  

                  Fbc = 3.56*10^-8 N

                  vector Fbc = Fbc* [ cos (β) i - sin (β) j ]

                  vector Fbc = 3.56*10^-8* [ cos (53.13°) i - sin (53.13°) j ]

                  vector Fbc = [ 2.136 i - 2.848 j ]*10^-8 N

- The Net gravitational force can now be determined from vector additon of Fac and Fbc:

                  Fc = vector Fac + vector Fbc

                  Fc = [ - 2.136 i - 1.602 j ]*10^-8  + [ 2.136 i - 2.848 j ]*10^-8

                  Fc = [ - 4.45 * 10^-8 j ] N  

3 0
3 years ago
Compare and Contrast Potential Energy with Thermal Energy
Brilliant_brown [7]
Potential energy is energy stored due to its position. Thermal energy is energy released as heat
8 0
3 years ago
Can there be displacement of an object in the absence of any force acting on it? Think, Discuss it with your friends and teacher
Fudgin [204]

Answer:

An object can have a displacement in the absence of any external force acting on it

Explanation:

When a object moves with a constant velocity (v), then it gets displaced in the direction of motion but the net external force experienced by the object is zero.

F  external  =ma

If object moves with constant velocity, acceleration is zero.

Since, a=0  ⟹F  external  =0

Using  s=ut+  1/2 at  ^2

 ⟹    Displacement    s=ut    (∵a=0)

Hence, an object can have a displacement in the absence of any external force acting on it

Hope this helped you:)

5 0
3 years ago
The measured value of the speed of light is about 300,000 km/s. suppose a futuristic space train is traveling at 200,000 km/s wi
Gwar [14]
The speed of light generally would be 300000km/s but since the train is moving in the same direction as the light it would apparently appear to be 100000km/s
3 0
3 years ago
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