Probability that both roads from a to b are blocked is the product of the individual probabilities, i.e.
P(~ab)=0.25*0.25=0.0625
Similarly
P(~bc)=0.25*0.25=0.0625
Probability that EITHER one or both of ab and bc are blocked is the sum of the probabilities:
P(~ab ∪ ~bc)=0.0625+0.0625=0.125
(recall that one cannot travel from a to c if either ab or bc is blocked.)
Therefore the probability that there exists an open route from a to c
= P(ac) = 1-P(~ab ∪ ~bc)
= 1 - 0.125
=0.875
Answer:
Step-by-step explanation:
m∠1=m∠3
m∠2=m∠4
3*(m∠1+m∠3)=m∠2+m∠4
3*(m∠1+m∠1)=m∠2+m∠2
3×2 m∠1=2 m∠2
m∠2=3 m∠1
now m∠1+m∠2=180°
m∠1+3 m ∠1=180
4 m∠1=180
m∠1=180/4=45°
m∠3=45°
m∠2=180-m∠1=180-45=135°
m∠4=135°
Another effective strategy for helping students improve their mathematics performance is related to solving word problems. More specifically, it involves teaching students how to identify word problem types based on a given problem’s underlying structure, or schema. Before learning about this strategy, however, it is helpful to understand why many students struggle with word problems in the first place.
Difficulty with Word Problems
Most students, especially those with mathematics difficulties and disabilities, have trouble solving word problems. This is in large part because word problems require students to:
Answer:
The soda costs 2.20 and the sandwich costs 7.70
Step-by-step explanation:
To find this, set the soda cost as x. We now know that the sandwich cost is 3.5x. Add these together and set equal to 9.90
x + 3.5x = 9.90
4.5x = 9.90
x = 2.20
This is the cost of the soda. Now we can multiply that by 3.5 to get the sandwich cost.
3.5 * 2.20 = 7.70
