Which is NOT an INHERITED TRAIT?

Two particles are fixed to an x axis: particle 1 of charge −1.50 ✕ 10−7 c at x = 6.00 cm, and particle 2 of charge +1.50 ✕ 10−7

sleet_krkn [62]

Answer : $\underset{E_{R}}{\rightarrow} =-2.44\times10^{5}\ \widehat{i} \ \dfrac{N}{C}$

Explanation :

Given that,

Charge of particle 1 = $-1.50\times10^{-7} c$

Distance x = 6 cm

Charge of particle 2 = $1.50\times10^{-7} c$

Distance x = 27 cm

Total distance = $\dfrac{6+27}{2}$

$r = 16.5\ cm$

Particle 1 is at (6,0) and particle 2 is at (27,0) .

Therefore, midway (16.5, 0)

Now, $r = \dfrac{|6-16.5|}{2} = \dfrac{|27-16.5|}{2} = 10.5\ cm$

Formula of electric field

$E = \dfrac{1}{4\pi\epsilon_{0}}\times\dfrac{q}{r^{2}}$

Now, the the electric field due to particle 1

$\underset{E}{\rightarrow}\ = -\dfrac{9\times10^{9}\times1.50\times10^{-7 }}{10.5}\ \widehat{i} \dfrac{N}{C}$

$\underset{E}{\rightarrow} = \dfrac{13.5\times10^{2}}{(10.5\times10^{-2})^{2}}\widehat{i} \dfrac{N}{C}$

$\underset{E}{\rightarrow} = -1.22\times10^{5}\ \widehat{i} \ \dfrac{N}{C}$

Similarly, the electric field due to particle 2

$\underset{E}{\rightarrow} = -1.22\times10^{5}\ \widehat{i} \ \dfrac{N}{C}$

Resultant Electric field

$\underset{E_{R}}{\rightarrow} = \underset{E_{1}}{\rightarrow} + \underset{E_{2}}{\rightarrow}$

$\underset{E_{R}}{\rightarrow} = -2.44\times10^{5}\ \widehat{i} \ \dfrac{N}{C}$

Hence, this is the required answer.

3 0

3 years ago

c) If the ice block (no penguins) is pressed down even with the surface and then released, it will bounce up and down, until fri

eduard

Answer:

y = 20.99 V / A

there is no friction y = 20.99 h

Explanation:

Let's solve this exercise in parts: first find the thrust on the block when it is submerged and then use the conservation of energy

when the block of ice is submerged it is subjected to two forces its weight hydrostatic thrust

F_net= ∑F = B-W

the expression stop pushing is

B = ρ_water g V_ice

where rho_water is the density of pure water that we take as 1 10³ kg / m³ and V is the volume d of the submerged ice

We can write the weight of the body as a function of its density rho_hielo = 0.913 10³ kg / m³

W = ρ-ice g V

F_net = (ρ_water - ρ_ ice) g V

this is the net force directed upwards, we can find the potential energy with the expression

F = -dU / dy

ΔU = - ∫ F dy

ΔU = - (ρ_water - ρ_ ice) g ∫ (A dy) dy

ΔU = - (ρ_water - ρ_ ice) g A y² / 2

we evaluate between the limits y = 0, U = 0, that is, the potential energy is zero at the surface

U_ice = (ρ_water - ρ_ ice) g A y² / 2

now we can use the conservation of mechanical energy

starting point. Ice depth point

Em₀ = U_ice = (ρ_water - ρ_ ice) g A y² / 2

final point. Highest point of the block

$Em_{f}$ = U = m g y

as there is no friction, energy is conserved

Em₀ = Em_{f}

(ρ_water - ρ_ ice) g A y² / 2 = mg y

let's write the weight of the block as a function of its density

ρ_ice = m / V

m = ρ_ice V

we substitute

(ρ_water - ρ_ ice) g A y² / 2 = ρ_ice V g y

y = ρ_ice / (ρ_water - ρ_ ice) 2 V / A

let's substitute the values

y = 0.913 / (1 - 0.913) 2 V / A

y = 20.99 V / A

This is the height that the lower part of the block rises in the air, we see that it depends on the relationship between volume and area, which gives great influence if there is friction, as in this case it is indicated that there is no friction

V / A = h

where h is the height of the block

y = 20.99 h

7 0

4 years ago

While studying projectile motion, we consider ideal scenarios, where the projectile travels along its trajectory only under the

Law Incorporation [45]

Drag is usually ignored because its effect on the horizontal velocity is usually negligible due to the short time of flight.

An object's surface area and geometry, along with the object's surrounding wind speed will affect the drag force.

In most cases, drag force will cause the object to land horizontally closer to the predicted landing point as drag is a resistive force.

4 0

3 years ago

Read 2 more answers

Katie traveled southwest a distance of 4000m on a bicycle in 5400s. What is her velocity?

nlexa [21]

The correct answer would be 1.35m/s sw.

7 0

3 years ago

Identify the physical property of a material that plays an important role in determining if the collision is elastic or not base

Nutka1998 [239]

Answer:

They are spherical and hollow (not compact or dense)

Explanation:

An elastic collision is a form of a collision where kinetic energy and momentum are conserved in the process. When there is zero loss of kinetic energy and momentum, it is called a perfectly elastic collision.

This form of collision is observed in atmospheric gases and colliding balls which happens to be spherical and hollow.

7 0

3 years ago