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3 years ago

About how many weeks does it take the Moon to go from a full Moon phase to a third quarter phase? A. 1 B. 2 C. 3 D. 4

Physics

1 answer:

Lostsunrise [7]3 years ago

3 0

The answer is D) About 4.
~Deceptiøn

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A hummingbird flies forward and backward. Its motion is shown on the above graph of horizontal Position and

harina [27]

Answer:

The hummingbird travels the total distance is 10 m

Explanation:

Given that,

A hummingbird flies forward and backward.

According to figure,

We know that,

The total distance is equal to the sum of all distance.

Forward direction is positive and backward direction is negative.

We need to calculate the hummingbird travels the total distance

Using figure,

$D=d_{1}+d_{2}+d_{3}+d_{4}$

Put the value into the formula

$D=6+(-4)+2+6$

$D=10\ m$

Hence, The hummingbird travels the total distance is 10 m.

8 0

3 years ago

A baseball leaves a bat with a horizontal velocity of 20 m/s. In a time of 0.25 s, How far will it have traveled horizontally?

Maurinko [17]

Distance traveled by the ball is given by

$distance = speed \times time$

here we know that

speed = 20 m/s

times = 0.25 s

now we have

$distance = 20 \times 0.25$

$distance = 5 m$

so ball will travel 5 m distance in the given interval of time

6 0

3 years ago

Which unit of measurement is included in the International System of Unit! (si)?

ozzi

Answer:

See the explanation below

Explanation:

There are several measures for the international system of measures. Let's name some and their representation symbol.

meter = [m]

time = [s] = seconds

mass = [kg] = kilograms

Temperature = [°C] = celcius degrees

Power = [W] = watts.

Force = [N] = Newtons

3 0

3 years ago

A rock is launched at angle theta=53.2∘ above the horizontal from an altitude of ℎ=182 km with an initial speed ????0=1.61 km/s.

Mariulka [41]

Answer:

The rock's final speed at the required altitude will be 42.24 m/s.

Explanation:

Let's start by finding the initial vertical speed.

Vertical Speed = 1.61 * Sin (53.2°)

Vertical Speed = 0.8 m/s

We want to know the speed of the rock when it is at an altitude of 91 km.

The total displacement of the rock from its starting position will thus be equal to -91 km

We can use this in the following equation:

$s=u*t+\frac{1}{2} (a*t^2)$

$-91=0.8*t+\frac{1}{2} (-9.8*t^2)$

t = 4.3918 seconds

Thus it takes 4.3918 seconds to reach the required altitude. We can now find the speed as follows:

$V=U+at$

$V=0.8+(-9.8)*(4.3918)$

$V = -42.24$

Thus the rock's final speed at the required altitude will be 42.24 m/s.

8 0

3 years ago

Read 2 more answers

A uniform horizontal rod of mass Mand length rotates with angular velocity about a vertical axis through its center. Attached to

Lostsunrise [7]

Answer:

Explanation:

3 0

2 years ago