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2 years ago

Which types of waves have the shortest wavelength?

1 answer:

8 0

Radio waves, infrared rays, visible light, ultraviolet rays, X-rays, and gamma rays are all types of electromagnetic radiation. Radio waves have the longest wavelength, and gamma rays have the shortest wavelength.

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A Gaussian surface in the form of a hemisphere of radius R = 3.04 cm lies in a uniform electric field of magnitude E = 1.64 N/C.

Likurg_2 [28]

Answer:

Part a)

$\phi = -4.76 \times 10^{-3} Nm^2/C$

Part b)

$\phi_{curved} = 4.76 \times 10^{-3} Nm^2/C$

Explanation:

Part a)

Electric flux entering into the base

so it is given as

$\phi = E.A$

$\phi = - EA$

$\phi = -(1.64)(\pi r^2)$

$\phi = -(1.64)(\pi\times 0.0304^2)$

$\phi = -4.76 \times 10^{-3} Nm^2/C$

Part b)

Now since we know that there is no enclosed charge in the hemisphere

so net flux must be zero

$\phi_{curved} + \phi_{flat} = 0$

$\phi_{curved} - 4.76 \times 10^{-3} = 0$

$\phi_{curved} = 4.76 \times 10^{-3} Nm^2/C$

7 0

2 years ago

If a copper tube has current flowing to the right in the presence of a magnetic field going forward ("into the board"), we expec

Citrus2011 [14]

Answer:

False, because current flow has no effect in the weight of a conductor.

Explanation:

Current flow has no effect in the weight of a conductor. Thus, the weight on the scale will be the same when current is flowing and when current is not flowing in the copper tube.

Therefore, If a copper tube has current flowing to the right in the presence of a magnetic field going forward ("into the board"), we expect the weight on the scale to be the same whether current is flowing or not.

6 0

3 years ago

What is the threshold velocity vthreshold(water) (i.e., the minimum velocity) for creating Cherenkov light from a charged partic

VladimirAG [237]

Complete Question

The complete question is shown on the first uploaded image

Answer:

$v_w = 2.256 *10^{8} \ m/s$

$v_e = 2.21 *10^{8} \ m/s$

The correct option is B

Explanation:

From the question we are told that

The refractive index of water is $n_w = 1.33$

The refractive index of ethanol is $n_e = 1.36$

Generally the threshold velocity for creating Cherenkov light from a charged particle as it travels through water is mathematically evaluated as

$v_w = \frac{c}{n_w }$

Where c is the speed of light with value $c = 3.0 *10^{8} \ m/s$

$v_w = \frac{3.0 *10^{8}}{1.33 }$

$v_w = 2.256 *10^{8} \ m/s$

Generally the threshold velocity for creating Cherenkov light from a charged particle as it travels through water is mathematically evaluated as

$v_e = \frac{ c}{n_e }$

=> $v_e = \frac{3.0 *10^{8}}{1.36 }$

=> $v_e = 2.21 *10^{8} \ m/s$

4 0

3 years ago

Two people are standing on a 3.12-m-long platform, one at each end. The platform floats parallel to the ground on a cushion of a

Ann [662]

Answer:

The magnitude of displacement is 0.082m

Explanation:

While the ball is in motion,we have MV + mv= 0 ...eq1

Where M = combined mass of the platform and the two people.

V = velocity of the platform

m = mass of the ball

v = velocity of the ball

The distance that the platform moves is given by:

X = Vt ...eq2

Where t is the time that the ball is in the air.

The time the ball is in the air is given by:

L/(v-V) ...eq3

Where L is the length of the platform

The quantity(v-V) = velocity of the ball relative to the platform.

Combining eq2 and eq3

X = (V/(v - V))L

From eq1 , the ratios of the velocities is V/v = -m/M

X = (V/v)L / (1 - (V/v) = (-m/M) L /(1+ (m/M))

X = -mL/(M + m)

X = - (3.36kg × 3.12m) /( 119kg + 3.36kg)

X = - 10.48/ 122.36

X = -0.082m

The minus sign implies that the displacement of the platform is in the opposite direction to the displacement of the ball.

Therefore, the distance moved by the platform is the magnitude of this displacement 0.082m.

7 0

3 years ago

Read 2 more answers

Spidermans nemesis electro delivers 4kj of electrical energy in half a second how much power does it draw from the mains?

Elodia [21]

Power delivered = (energy delivered) / (time to deliver the energy)

Power delivered = (4,000 J) / (0.5 sec)

Power delivered = 8,000 watts

I'm a little surprised to learn that Electro draws his power from the mains. This is VERY good news for Spiderman ! It means that Spiderman can always avoid tangling with Electro ... all he has to do is stay farther away from Electro than the length of Electro's extension cord.

But OK. Let's assume that Electro draws it all from the mains. Then inevitably, there must be some loss in Electro's conversion process, between the outlet and his fingertips (or wherever he shoots his bolts from).

The efficiency of Electro's internal process is

<em>(power he shoots out) / (power he draws from the mains) </em>.

So, if he delivers energy toward his target at the rate of 8,000 watts, he must draw power from the mains at the rate of

<em>(8,000 watts) / (his internal efficiency) . </em>

4 0

3 years ago

Read 2 more answers