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4 years ago

By what factor must the sound intensity be increased to increase the sound intensity level by 12.5 db ?

1 answer:

8 0

The sound has a unit of measurement. In physics, there are two measurements: in intensity (Watts per square meterI or in decibels. The most common unit of measurement is in decibels or dB. In fact, the threshold of hearing when it comes to measuring noise is in terms of decibels.

To convert decibels to intensity in W/^2, the equation is

dB = 10log(I/I0), where I0 is equal to 10^-16. It is an empirical constant for the standard reference intensity. Therefore,

12.5 = 10 log (I/10^-16)
I = 1.78 × 10^-15 W/m^2

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Two vectors A and B are added to give a resultant R. The components of A are Ax = -8.0 units and Ay = 6.0 units and the componen

Georgia [21]

Answer:

10.09 units

Explanation:

For the A

Ax = -8.0 units

Ay = 6.0 units

The resultant vector = Ra = $\sqrt{A^2_{x} + A^2_{y} }$

Ra = $\sqrt{(-8)^2 + 6^2 }$ = 10 units

For B

Bx = 1.0 units

By = -1.0 units

The resultant vector = Rb = $\sqrt{B^2_{x} + B^2_{y} }$

Rb = $\sqrt{1^2 + (-1)^2 }$ = $\sqrt{2}$ units

Adding these two vectors A and B together, magnitude of vector R is

R = $\sqrt{R^2_{a} + R^2_{b} }$

R = $\sqrt{10^2 + (\sqrt{2} ) ^2}$ = 10.09 units

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4 years ago

What is the percent increase in the vapor pressure of water when the temperature increases by 1 °c from 14°c to 15°c.

Artemon [7]

The Vapor Pressure of water increases by 5.1%. when the temperature increases by 1 °c from 14°c to 15°c.

The vapor pressure of a liquid, sometimes referred to as the equilibrium pressure of a vapor above its liquid, is the pressure of the vapor produced by the evaporation of a fluid (or solid) over a sample of the liquid (or solid) in such a closed container (or solid).

Vapor pressure is the term for the force that is produced as liquids evaporate. Three factors commonly have an effect on a vapor press: surface area, intermolecular forces, and temperature. The vapor pressures of molecules change with temperature.

To know more about Vapor Pressure visit : brainly.com/question/14718830

#SPJ4

6 0

1 year ago

Before Sam left for work, he noticed that his car was covered with snow and so went out and started the engine to let it warm up

meriva

The question before or after this one on your homework has something to do with airplanes. These answer choices belong with that airplane question. They're not the choices for the snowy-car question. None of them is the correct answer.

You'll want to look for a set of choices that might include "conduction" or "convection".

7 0

4 years ago

You launch a model rocket that has a mass of 2 kg. At a height of 400 m, it is traveling at 150 m/s. What is its kinetic energy

Feliz [49]

Explanation:

KE = ½ mv²

KE = ½ (2 kg) (150 m/s)²

KE = 22,500 J

3 0

3 years ago

A shopper pushes a 5.32 kg grocery cart

Juli2301 [7.4K]

Answer:

$\text { acceleration of the cart is } 10.94 \mathrm{m} / \mathrm{s}^{2}$

Explanation:

According to “Newton's second law”

“Force” is “mass” times “acceleration”, or F = m× a. This means an object with a larger mass needs a stronger force to be moved along at the same acceleration as an object with a small mass

Force = mass × acceleration

$\text { Acceleration }=\frac{\text { force }}{\text { mass }}$

Given that,

Mass = 5.32 kg

$\text { Force }=12.7 \mathrm{N} \text { forces at }-28.7^{\circ}$

$x=-28.7^{\circ}$

F = 12.7N

Normal force = mg + F sinx,

“m” being the object's "mass",

“g” being the "acceleration of gravity",

“x” being the "angle of the cart"

$\mathrm{g}=9.8 \mathrm{m} / \mathrm{s}^{2}\text { (g is referred to as the acceleration of gravity. Its value is } 9.8 \mathrm{m} / \mathrm{s}^ 2 \text { on Earth })$