Answer - There are three ways an object can accelerate: a change in velocity, a change in direction, or a change in both velocity and direction.
Earth's dynamic processes allow our planet to recycle air, surface materials, and water. The correct answer is D.
Answer:

Explanation:
We know that heat relates to mass, specific heat and variation of temperature experimented because of this heat through the equation
. The heat released by the unknown material is absorbed by water, so we have
, and we can write:

Since thermal equilibrium is reached we know that
, where we have added
to convert the temperature from Celsius to Kelvin, as <em>we must do</em>. Since we want the specific heat of the unknown material, we do:

Which for our values is:

Answer:
Final velocity will be 314.6 m/sec
Distance traveled = 1314.24 m
Explanation:
We have given initial velocity u = 233 m/sec
Acceleration 
Time t = 4.8 sec
From first equation of motion
, here v is final velocity, u is initial velocity and t is time
So 
Now we have to find distance traveled
From second equation of motion

So distance traveled in given time will be 1314.24 m