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4 years ago

By what factor must the sound intensity be increased to increase the sound intensity level by 12.5 db ?

1 answer:

8 0

The sound has a unit of measurement. In physics, there are two measurements: in intensity (Watts per square meterI or in decibels. The most common unit of measurement is in decibels or dB. In fact, the threshold of hearing when it comes to measuring noise is in terms of decibels.

To convert decibels to intensity in W/^2, the equation is

dB = 10log(I/I0), where I0 is equal to 10^-16. It is an empirical constant for the standard reference intensity. Therefore,

12.5 = 10 log (I/10^-16)
I = 1.78 × 10^-15 W/m^2

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A small object carrying a charge of -2.50 nc is acted upon by a downward force of 18.0 nn when placed at a certain point in an e

Vesna [10]

Missing question in the text:
"A.What are the magnitude and direction of the electric field at the point in question?

B.<span>What would be the magnitude and direction of the force acting on a proton placed at this same point in the electric field?"</span>

<span>Solution:

A) A charge q </span>under an electric field of intensity E will experience a force F equal to:

$F=qE$

In our problem we have $q=-2.5 nC=-2.5\cdot 10^{-9} C$ and $F=18 nN = 18 \cdot 10^{-9} N$ , so we can find the magnitude of the electric field:

$E= \frac{F}{q}= \frac{18\cdot 10^{-9}N}{2.5\cdot 10^{-9}C}=7.2 V/m$

The charge is negative, therefore it moves against the direction of the field lines. If the force is pushing down the charge, then the electric field lines go upward.

B) The proton charge is equal to

$e=1.6\cdot 10^{-19} C$

Therefore, the magnitude of the force acting on the proton will be

$F=eE=1.6\cdot 10^{-19} C \cdot 7.2 V/m=1.15 \cdot 10^{-18} N$

And since the proton has positive charge, the verse of the force is the same as the verse of the field, so upward.

7 0

3 years ago

A cord of mass 0.65 kg is stretched between two supports 8.0 m apart. If the tension in the cord is 120 N, how long will it take

DedPeter [7]

The time taken by the pulse to travel from one support to the other is 0.208 s.

<h3>Given:</h3>

The mass of the cord is m = 0.65 kg.

The distance between the supports is, d = 8.0 m.

The tension in the cord is T = 120 N.

The time taken by the pulse to travel from one support to the other is given as,

$v=\frac{d}{t}$

$t=\frac{d}{v}$

Here, v is the linear velocity of a pulse. Its value is,

$v=\sqrt{\frac{T d }{m} }$

$v=\sqrt{\frac{120 * 8}{0.65} }$

$v= 38.43 m/s$

Then,

$t=\frac{8}{38.43}$

$t=0.208 s$

Thus, the time taken by the pulse to travel from one support to the other is 0.208 s.

Learn more about tension here:

brainly.com/question/24994188

#SPJ4

7 0

1 year ago

Although planets orbit the Sun in ellipses, all the planetary orbits are fairly close to circular and not very eccentric.

Nutka1998 [239]

Answer:

False

Explanation:

The Sun rotates in this same, right-hand-rule direction. All planetary orbits lie in nearly the same plane. All planetary orbits are nearly circular (eccentricity near zero).

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8 0

2 years ago

What happens to the atoms that make up hydrogen fuel as it burns?

ale4655 [162]

Answer:

Get turned Into Water.

Explanation:

Combustion of Hydrogen involves combining oxygen and hydrogen essentially so when oxygen and hydrogen combine water is produced, following chemical equation describes this process.

$H_{2} +O_{2}=2(H_{2}O)$ .

Resulting product is two molecules of water.

4 0

3 years ago

What can iron filings sprinkled on a piece of paper demonstrate?

jolli1 [7]

<span>c the pattern of the magnetic fields lines</span>

6 0

3 years ago