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valkas [14]
4 years ago
11

Find τf, the torque about point p due to the force applied by the achilles' tendon.

Physics
1 answer:
Luba_88 [7]4 years ago
3 0
The formula for the torque is
<span>τf = p F
where
</span><span>τf is the torque
p is the distance where the force is applied by the tendon
F is force applied by the tendon

If there are given values, substitute in the equation and solve for the torque.</span>
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Can an objects displacement be greater than or equal to the objects distance?
Reptile [31]
If you say displacement is greater than distance, you will contradict the above statement. Displacement is always less than or equal to distance. Note that distance is a scalar whereas displacement is a vector.So' displacement cannot be more than distance.
6 0
4 years ago
A ball is thrown horizontally from the top of a building 54 m high. The ball strikes the ground at a point 35 m horizontally awa
Ivanshal [37]

Answer:

V=34.2 m/s

Explanation:

Given that

Height , h= 54 m

Horizontal distance , x = 35 m

Given that , the ball is thrown horizontally , therefore the initial vertical velocity will be zero.

In vertical direction :

We know that

V^2_y=U^2_y+2 g h

Now by putting the values in the above equation we got

V^2_y=U^2_y+2 g h

V^2_y=0^2+2\times 9.81 \times 54

Assume g= 9.81 m/s^2

Thus

V^2_y=1059.48

V_y=\sqrt{1059.48}\ m/s

V_y=32.54 m/s

We also know that

V_y=U_y+ g\times t

32.54=9.81\times t

t=\dfrac{32.54}{9.81}=3.31\ s

In horizontal direction :

x=U_x\times t

U_x=\dfrac{35}{3.31}=10.54\ m/s

Thus the resultant velocity

V=\sqrt{V^2_y+U^2_x}

V=\sqrt{32.54^2+10.54^2}=34.2\ m/s

V=34.2 m/s

Therefore the velocity will be 34.2 m/s.

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4 years ago
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hodyreva [135]

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8 0
2 years ago
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A pump lifts water from a lake to a large tank 20 m above the lake. How much work against gravity does the pump do as it transfe
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Answer:

980 kJ

Explanation:

Work = change in energy

W = mgh

W = (1000 kg/m³ × 5.0 m³) (9.8 m/s²) (20 m)

W = 980,000 J

W = 980 kJ

The pump does 980 kJ of work.

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A whale swims due east for a distance of 6.9 km, turns around and goes due west for 1.8 km, and finally turns around again and h
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Answer:

Explanation:

a) Total distance traveled by the whale = 6.9 km + 1.8 km + 3.7 km = 12.4 km

b) the magnitude and the direction of the displacement of the whale = 6.9 km due east - 1.8 km due west = 5.1 due east

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d) average velocity in km / h = total displacement / total time = 8.8 km / 0.5 h = 17.6 km/h

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