Pv=nRT
where,p=199, R(constant)=8.314, V=4.67 T=30C=293K
n=pv/RT=0.38 moles
Just find the percent mass of oxygen in sucrose again. and then multiply that by 50.00.
During a reaction, there are reactants and products. Reactants are the elements that are being added. Products are the result of the reactants.
2Na + Cl2 are the reactants.
2NaCl is the Product.
I hope this helps!
For this problem we assume that oxygen is an ideal gas. So, we use the equation PV=nRT where P is pressure, V is the volume, n is the number of moles, R is a universal constant and T is the temperature. We first solve for the number of moles n. Then, using the molar mass of oxygen we convert it to grams.
PV=nRT
n = PV / RT
n = 3.23 (8.5) / 0.08206 (32+273.15)
n = 1.0964 mol
mass = 1.0964 mol (32g / 1 mol) = 35.09 g O2
