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ArbitrLikvidat [17]
3 years ago
13

for the reaction C+2H2= Ch4 how many molecules of hydrogen are required to produce 14 grams of methane Ch4?

Chemistry
1 answer:
Nina [5.8K]3 years ago
5 0

Answer:

mass of CH4 = 14

Molecular mass of CH4 16.04gmol

No of mole of CH4 = 14/16.04

No of mole of CH4 = 0.8728mol

Stoichiometrically, from the above

2 Molecules of Hydrogen will produce 1molecule of methane

Therefore, 2*0.8728 mole of Hydrogen will produce 0.8728mol of Methane.

The no of molecule of hydrogen is 1.7456

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Need help <br>1/6 + 1/8 =
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7 0
2 years ago
The compound Xe(CF3)2 decomposes in afirst-order reaction to elemental Xe with a half-life of 30. min.If you place 7.50 mg of Xe
Irina-Kira [14]

Answer:

t=147.24\ min

Explanation:

Given that:

Half life = 30 min

t_{1/2}=\frac{\ln2}{k}

Where, k is rate constant

So,  

k=\frac{\ln2}{t_{1/2}}

k=\frac{\ln2}{30}\ min^{-1}

The rate constant, k = 0.0231 min⁻¹

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration

Given that:

The rate constant, k = 0.0231 min⁻¹

Initial concentration [A_0] = 7.50 mg

Final concentration [A_t] = 0.25 mg

Time = ?

Applying in the above equation, we get that:-

0.25=7.50e^{-0.0231\times t}

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750e^{-0.0231t}=25

x=\frac{\ln \left(30\right)}{0.0231}

t=147.24\ min

6 0
3 years ago
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