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3 years ago

for the reaction C+2H2= Ch4 how many molecules of hydrogen are required to produce 14 grams of methane Ch4?

Chemistry

1 answer:

Nina [5.8K]3 years ago

5 0

Answer:

mass of CH4 = 14

Molecular mass of CH4 16.04gmol

No of mole of CH4 = 14/16.04

No of mole of CH4 = 0.8728mol

Stoichiometrically, from the above

2 Molecules of Hydrogen will produce 1molecule of methane

Therefore, 2*0.8728 mole of Hydrogen will produce 0.8728mol of Methane.

The no of molecule of hydrogen is 1.7456

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D. I or Iodine

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2 years ago

Which of the following is a characteristic property of noble gases? A. They only react with each other B. They do not react chem

tresset_1 [31]

Answer:

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3 years ago

1. Which has the greatest heat capacity?

mash [69]

Answer:

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3 years ago

How many milliliters of a 0.285 M HCl solution are needed to neutralize 249 mL of a 0.0443 M Ba(OH)2 solution?

meriva

Answer:

$\large \boxed{\text{77.4 mL}}$

Explanation:

Ba(OH)₂ + 2HCl ⟶ BaCl₂ + H₂O

V/mL: 249

c/mol·L⁻¹: 0.0443 0.285

1. Calculate the moles of Ba(OH)₂

$\text{Moles of Ba(OH)$_{2}$} = \text{0.249 L Ba(OH)}_{2} \times \dfrac{\text{0.0443 mol Ba(OH)}_{2}}{\text{1 L Ba(OH)$_{2}$}} = \text{0.011 03 mol Ba(OH)}_{2}$

2. Calculate the moles of HCl

The molar ratio is 2 mol HCl:1 mol Ba(OH)₂

$\text{Moles of HCl} = \text{0.011 03 mol Ba(OH)}_{2} \times \dfrac{\text{2 mol HCl}}{\text{1 mol Ba(OH)}_{2}} = \text{0.022 06 mol HCl}$

3. Calculate the volume of HCl

$V_{\text{HCl}} = \text{0.022 06 mol HCl} \times \dfrac{\text{1 L HCl}}{\text{0.285 mol HCl}} = \text{0.0774 L HCl} = \textbf{77.4 mL HCl}\\\\\text{You must add $\large \boxed{\textbf{77.4 mL}}$ of HCl.}$

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3 years ago