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melomori [17]
3 years ago
14

How long will it take the cyclist to travel 400 meter?

Chemistry
1 answer:
yuradex [85]3 years ago
7 0
It depends on the mph

Please mark me as brainliest. I need brainliest to get to Ace (rank).
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1. What do microorganisms share in common?​
alexgriva [62]

Answer:

Bacterial species are typified by their diversity. There are three notable common traits of bacteria, 1) lack of membrane-bound organelles, 2) unicellular and 3) small (usually microscopic) size.

Explanation:

What Are the Characteristics Common to All Bacteria?

Single-Celled. Perhaps the most straightforward characteristic of bacteria is their existence as single-celled organisms. ...

Absent Organelles. ...

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DNA.

4 0
2 years ago
Propiedades Químicas del elemento Astato. por favor es urgente!
Zarrin [17]
I'm not to sure but try soy
4 0
3 years ago
A truck traveled at a constant speed for 6 hours. Then, it
gavmur [86]

Answer:

2.4 hrs

Explanation:

The constant speed of the truck for 6 hrs can be calculated by: speed=distance/time. Speed =(876-228)/6=648/6=108m/s. So the decreased speed = (108-13)=95m/h. Now, speed =distance /time We get 95m/h = 228/t. t=228/95 hrs = 2.4 hrs PLEASE MARK ME THE BRAINLIEST!!

7 0
3 years ago
Read 2 more answers
How many moles of koh are contained in 250 ml of a 2.0 m solution of koh
kotykmax [81]
.5 mols
Assuming that your 2.0 m is an M for molarity
I used the formula M=number of mold/L
Converted 250mL to .250L by dividing by 1000
4 0
3 years ago
Determine the molar mass of CuSO4 (the solute) in a 1.0M aqueous solution of CuSO4
inna [77]

Answer:

See explanation.

Explanation:

Hello,

In this case, we could have two possible solutions:

A) If you are asking for the molar mass, you should use the atomic mass of each element forming the compound, that is copper, sulfur and four times oxygen, so you can compute it as shown below:

M_{CuSO_4}=m_{Cu}+m_{S}+4*m_{O}=63.546 g/mol+32.00g/mol+4*16.00g/mol\\\\M_{CuSO_4}=159.546g/mol

That is the mass of copper (II) sulfate contained in 1 mol of substance.

B) On the other hand, if you need to compute the moles, forming a 1.0-M solution of copper (II) sulfate, you need the volume of the solution in litres as an additional data considering the formula of molarity:

M=\frac{n_{solute}}{V_{solution}}

So you can solve for the moles of the solute:

n_{solute}=M*V_{solution}

Nonetheless, we do not know the volume of the solution, so the moles of copper (II) sulfate could not be determined. Anyway, for an assumed volume of 1.5 L of solution, we could obtain:

n_{solute}=1mol/L*1.5L=1.5mol

But this is just a supposition.

Regards.

4 0
2 years ago
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