Answer:
10°C
Explanation:
Heat gain by water = Heat lost by the slice of pizza
Thus,
<u>For water: </u>
Volume = 50.0 L
Density of water= 1 kg/L
So, mass of the water:
Mass of water = 50 kg
Specific heat of water = 1 kcal/kg°C
ΔT = ?
For slice of pizza:
Q = 500 kcal
So,
ΔT = 10°C
Increase in temperature = 10°C
We assume that we have Ka= 4.2x10^-13 (missing in the question)
and when we have this equation:
H2PO4 (-) → H+ + HPO4-
and form the Ka equation we can get [H+]:
Ka= [H+] [HPO4-] / [H2PO4] and we have Ka= 4.2x10^-13 & [H2PO4-] = 0.55m
by substitution:
4.2x10^-13 = (z)(z)/ 0.55
z^2 = 2.31x 10^-13
z= 4.81x10^-7
∴[H+] = 4.81x10^-7
when PH equation is:
PH= -㏒[H+]
= -㏒(4.81x10^-7) = 6.32
Answer: a
Explanation:
Industry uses only about 18% while the others use around 70-90% of water.
YW!!! please mark branlest!!!! =^.^=
Answer:double displacement
Explanation:I just did it
Answer:
36.63 Torr
Explanation:
You need to use two expressions, one for pressure and the other with the relation of density and height of the column.
For the pressure:
P = h * d * g (1)
h is height.
d density
g gravity
The second expression put a relation between the densities and height of the column so:
d1/d2 = h1/h2 (2)
let 1 be the phthalate, and 2 the mercury.
Let's calculate first the relation of density:
d1/d2 = 13.53 / 1.046 = 12.93
Now with the first expression, we can calculate the pressure so:
P = hdg
We have two compounds so,
h1d1g = h2d2g ---> gravity cancels out
From here, we can solve for h2:
h2 = h1*(d1/d2)
replacing:
h2 = 459 / 12.53
h2 = 36.63 mm
1 mmHg is 1 torr, therefore the pressure of the gas in Torr would be 36.63 Torr
