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guapka [62]
3 years ago
5

A compound is 44.7% P and the rest O. Determine its emperical formula.

Chemistry
1 answer:
svet-max [94.6K]3 years ago
6 0

Answer:  

P₅O₁₂

<em>Explanation:  </em>

Assume that you have 100 g of the compound.  

Then you have 44.7 g P and 55.3 g O.  

1. Calculate the <em>moles</em> of each atom  

Moles of P  = 44.7 × 1/30.97 = 1.443 mol Al  

Moles of O = 55.3 × 1/16.00 = 3.456 mol O  

2. Calculate the <em>molar ratios</em>.  

P: 1.443/1.443 =   1  

O: 3.456/1.443 = 2.395

3. Multiply by a number to make the ratio close to an integer

P:  5 × 1         =  5

O: 5 × 2.395 = 11.97

3. Determine the <em>empirical formula </em>

Round off all numbers to the closest integer.  

P:   5

O: 12

The empirical formula is <em>P₅O₁₂</em>.  

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What is a property of a solution with a high pH? Select all that apply. *
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8 0
2 years ago
I need chemistry help! How would I set up these problems?
Bond [772]

Answer: -

1) 8.33 minutes

2) 118.39 in/ s

180.43 m/min

10.83 km/ hr

Explanation: -

Speed of light = 3 x 10⁸ m/s

Distance of the earth from the sun= 93 million miles

We know 1 million = 1,000,000

Also 1 mile = 1609 m

Distance of the earth from the sun= 93 million miles

= 93,000,000 miles.

= 1.5 x 10^{11} m

Time taken = \frac{Distance}{Speed}

= \frac{1.5 x [tex] 10^{11} m}{3 x 10⁸ m/s} [/tex]

= 500 s

= 500/ 60

= 8.33 minutes

2) Distance = 1 mile = 63360 inches

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= 8.92 x 60

= 535.2 s

Speed = \frac{distance}{time}

= \frac{63360 inches}{535.2 s}

= 118.39 in/ s

Distance = 1 mile = 63360 inches = 63360 x 2.54 cm = 63360 x 2.54 x 10^{-2} m

Time taken = 8.92 min

Speed = \frac{distance}{time}

= \frac{63360 x 2.54 x [tex] 10^{-2} m}{8.92 min} [/tex]

= 180.43 m/ min

1 m = 10⁻³ Km

1 min = 1/60 hour

1 m /min = 10⁻³ km/ \frac{1}{60 hour}

= 60/1000

=0.06 km/hr

180.43 m / min = 180 x 0.06 km / hr

= 10.93 km / hr

4 0
3 years ago
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