Answer:
You are looking for expected peaks in absorption spectra founded on structure of desired product, respectively on bound in desired compound. Every bond absorb specific energy from radiation which wavelength match to IR spectrum of light. Result of energy absorption is vibration of bond and bonded atoms (if they are not too heavy).That absorbed energy is seen as a peak in absorption spectra. These peaks are specific for each bound so you need to find peaks that mach to bounds in your desired compound and in that matter you can identify your compound.
In nuclear magnetic resonance you are looking for peaks specific for atoms in your desired compound (H or C atoms). When external magnetic field is applied, atom goes in higher energy state. When atoms goes "relaxing", it releasing energy that mach energy gap from relaxed end excited state. That energy is detected on nuclear magnetic resonance spectra and it depends on neighbor atom so you can determine the position of atoms and identify structure of desired compound.
For better results it is the best to combine these two methods.
Explanation:
Answer:
34.28 L ( 1.5*22.4 L)
Explanation:
Calculation of the moles of aluminum as:-
Mass = 55 g
Molar mass of aluminum = 26.981539 g/mol
The formula for the calculation of moles is shown below:
Thus,
According to the reaction:-
4 moles of aluminum react with 3 moles of oxygen gas
1 mole of aluminum react with 
moles of oxygen gas
2.0384 moles of aluminum react with 
moles of oxygen gas
Moles of oxygen gas = 1.5288 moles
At STP,
Pressure = 1 atm
Temperature = 273.15 K
Using ideal gas equation as:
where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 0.0821 L.atm/K.mol
Applying the equation as:
1 atm × V = 1.5288 mol × 0.0821 L.atm/K.mol × 273.15 K
⇒V = 34.28 L ( 1.5*22.4 L)
Answer:
Explanation:
A. Linear Relationships
x 2 4 6 8 10 12
y 4.4 8.8 13.2 17.6 22 26.4
(you can plot this by using the (x,y) coordinates for each pair above.)
B. y=2.2x
mass is 2.2 times larger than the volume.
C. The mass is 2.2 times the volume.
Here we have to get the 
of the reaction at 520 K temperature.
The of the reaction is 1.705 atm
We know the relation between and 
is 
, where = The equilibrium constant of the reaction in terms of partial pressure, = The equilibrium constant of the reaction in terms of concentration and N = number of moles of gaseous products - Number of moles of gaseous reactants.
Now in this reaction, PCl₃ + Cl₂ ⇄ PCl₅
Thus number of moles of gaseous product is 1, and number of moles of gaseous reactants are 2. Thus N = |1 - 2| = 1 mole
The given value of is 4.0×10⁻²
The molar gas constant, R = 0.082 L. Atm. mol⁻¹. K⁻¹ and temperature, T = 520 K.
On plugging the values in the equation we get,
Or, = 1.705 atm
Thus, the of the reaction is 1.705 atm
In the equation,
2Al(s) + 3Cl2(g) —> 2AlCl3(s),
the large number "3" in front of Cl2 indicates the the number of moles of Chlorine molecules needed to balance the equation.
Hope this will help you.
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