All categories

3 years ago

Q 1. Element M is a metal that forms compounds of the type MX2, MX3, and MX4, where X is a Chlorine (Cl).

Chemistry

1 answer:

SOVA2 [1]3 years ago

3 0

Answer:

See explanation

Explanation:

The ionic radius of metal M decreases as the charge on the metal M increases. The ionic radius is generally defined as the distance between the nucleus and the outermost electron of the ion. Hence, ionic radius becomes much lesser as the magnitude of the positive charge increases.

It is obvious from the various formulae of metal chlorides in the question that the metal forms cations M^2+, M^3+ and M^4+ respectively. The order of decreasing ionic radius of the compounds is;

MX2 > MX3 > MX4

You might be interested in

Calculate the pH at the equivalence point for the titration of 0.110 M methylamine (CH3NH2) with 0.110 M HCl. The Kb of methylam

nikklg [1K]

The reaction between the reactants would be:

CH₃NH₂ + HCl ↔ CH₃NH₃⁺ + Cl⁻

Let the conjugate acid undergo hydrolysis. Then, apply the ICE approach.

CH₃NH₃⁺ + H₂O → H₃O⁺ + CH₃NH₂
I 0.11 0 0
C -x +x +x
E 0.11 - x x x

Ka = [H₃O⁺][CH₃NH₂]/[CH₃NH₃⁺]

Since the given information is Kb, let's find Ka in terms of Kb.

Ka = Kw/Kb, where Kw = 10⁻¹⁴

So,
Ka = 10⁻¹⁴/5×10⁻⁴ = 2×10⁻¹¹ = [H₃O⁺][CH₃NH₂]/[CH₃NH₃⁺]
2×10⁻¹¹ = [x][x]/[0.11-x]
Solving for x,
x = 1.483×10⁻⁶ = [H₃O⁺]

Since pH = -log[H₃O⁺],
pH = -log(1.483×10⁻⁶)
<em>pH = 5.83</em>

4 0

3 years ago

calculate how much acid (acetic acid) and how much conjugate base (sodium acetate) must be used to make 500ml of a 0.8m acetate

kirza4 [7]

For the desired pH of 5.76, 0.365 mol of acetate and 0.035 mol of acid are to be added

let the concentration of acetate be x

then the concentration of acid will be (0.8 - x)

pKa of acetate buffer = 4.76

pH = pKa + log([acetate]/[acid])

⇒4.76 = 4.76 + log(x/(0.8-x))

⇒log(x/(0.8-x)) = 0

⇒x/(0.8-x) = 1

⇒x = 0.4

Therefore

[acetate] = x = 0.4

[acid] = 0.8-x =0.4 M

number of mol = concentration *(volume in mL)

number of mol of acetate = 0.4*0.5

= 0.20 mol

number of mol acid = 0.4*0.5

= 0.20 mol

when desired pH = 5.76

pH = pKa + log([acetate]/[acid])

⇒5.76 = 4.76 + log(x/(0.8-x))

⇒log(x/(0.8-x)) = 1

⇒x/(0.8-x) = 10

⇒x = 8 - 10x

⇒x = 8/11

⇒x= 0.73

[acetate] = x= 0.73

[acid] = 0.8-x = 0.07 M

number of mol = concentration * (volume in mL)

number of mol acetate to be added = 0.73*0.5 = 0.365 mol

number of mol acid to be added = 0.07*0.5 = 0.035 mol

Problem based on acetic acid required to maintain a certain pH

brainly.com/question/9240031

#SPJ4

4 0

1 year ago

What is an organ that absorbs water and vitamin K from digested food

TEA [102]

The Large intestine absorbs water and vitamin K from digested food.

3 0

3 years ago

Pure sodium metal explodes when it makes contact with water. In its natural state, chlorine is a deadly, poisonous gas. When the

RideAnS [48]

https://do-work-zone.com/?mref=hello69

8 0

3 years ago

Read 2 more answers

Determine the density of a liquid from the following data: Mass of the

Tanya [424]

Answer:0.477 g/ml

Explanation:

Density=(40.14-33.79)/13.3 ml

Density=6.35/13.3

Density=0.477 g/ml

6 0

3 years ago