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Oliga [24]
3 years ago
8

In a single displacement reaction between Sodium Phosphate and Barium, how much of each product (in grams) will be formed from 1

0.0 grams of Barium? Show your work.
Chemistry
1 answer:
mixer [17]3 years ago
4 0

Answer:

14.6 g of barium phosphate

3.35 g of sodium metal

Explanation:

2Na3PO4(aq) + 3Ba(s) -------> Ba3(PO4)2(aq) + 6Na(s)

The first step in any such reaction is to but down the balanced reaction equation according to the stoichiometry of the reaction.

The two products formed are barium phosphate and sodium metal.

Number of moles of barium corresponding to 10.0g of barium = mass of barium/ molar mass of barium

Molar mass of barium = 137.327 g

Number of moles of barium = 10/137.327

Number of moles of barium = 0.0728 moles

For barium phosphate;

3 moles of barium yields 1 mole of barium phosphate

0.0728 moles yields 0.0728 moles × 1/3 = 0.0243 moles of barium phosphate

Molar mass of barium phosphate = 601.93 g/mol

Therefore mass of barium phosphate = 0.0243 moles × 601.93 g/mol = 14.6 g of barium phosphate

For sodium metal

3 moles of barium yields 6 moles of sodium metal

0.0728 moles of barium yields 0.0728 × 6 / 3 = 0.1456 moles of sodium

Molar mass of sodium metal= 23 gmol-1

Mass of sodium metal= 0.1456g × 23 gmol-1 = 3.35 g of sodium metal

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C) The molecules become separated from each other.

Explanation:

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Which term describes a substance that increases the concentration of hydroxide (OH-) ions in solution? *
saul85 [17]

Answer:

The correct answer to the following question will be "Arrhenius base".

Explanation:

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So that the above is the right answer.

8 0
3 years ago
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How many atoms of cobalt are in one formula unit of cobalt (III) oxide? one two three six
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What is the pressure of 4 moles of helium in a 50 L tank at 308k using PV=nRT
Ilya [14]

Hey there!:

p = ??

n = 4 moles

V = 50 L

T = 308 K

R =  0.082 atm

p*V = n * R * T

p * 50 = 4 * 0.082 * 308

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Hope that helps!


8 0
2 years ago
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1. The solubility of AgNO3 at 20°C is 222.0g AgNO3/100g H2O. What mass of AgNO3 can be dissolved in 250 g of water at 20°C? Reca
neonofarm [45]

Answer :

(1) The mass of silver nitrate is, 555 g

(2) The solubility of the gas will be, 0.433 g/L

<u>Solution for Part 1 :</u>

From the given data we conclude that

In 100 gram of water, the amount of silver nitrate = 222 g

In 250 gram of water, the amount of silver nitrate = \frac{222}{100}\times 250=555g

Therefore, the mass of silver nitrate is, 555 g

<u>Solution for Part 2 :</u>

Formula used : S_1P_1=S_2P_2     (at constant temperature)

where,

S_1 = initial solubility of methane gas = 0.026 g/L

S_2 = final solubility of methane gas

P_1 = initial pressure of methane gas = 1 atm

P_2 = final pressure of methane gas = 0.06 atm

Now put all the given values in the above formula, we get the solubility of methane gas.

(0.026g/L)\times (1atm)=S_2\times (0.06atm)

S_2=0.433g/L

Therefore, the solubility of the gas will be, 0.433 g/L

5 0
3 years ago
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