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Daniel [21]
2 years ago
9

Today I meant to look for my missing watch, but I could never find the time.

Engineering
2 answers:
belka [17]2 years ago
6 0

Answer:

the time in north america is 1:28

Explanation:

xxMikexx [17]2 years ago
5 0

Answer:

haha i get it

Explanation:

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Today I meant to look for my missing watch, but I could never find the time.
xxMikexx [17]

Answer:

haha i get it

Explanation:

5 0
2 years ago
Read 2 more answers
When we say that communication is
Harlamova29_29 [7]

Answer:

Communication is simply the act of transferring information from one place, person or group to another. Every communication involves (at least) one sender, a message and a recipient.

Explanation:

3 0
2 years ago
Assume a function requires 20 lines of machine code and will be called 10 times in the main program. You can choose to implement
Volgvan

Answer:

"Macro Instruction"

Explanation:

A macro definition is a rule or pattern that specifies how a certain input sequence should be mapped to a replacement output sequence according to a defined procedure. The mapping process that instantiates a macro use into a specific sequence is known as macro expansion.

It is a series of commands and actions that can be stored and run whenever you need to perform the task. You can record or build a macro and then run it to automatically repeat that series of steps or actions.

7 0
3 years ago
Sarah needs to create an architectural drawing for a museum building with an inclined surface. Which presentation view will be t
prohojiy [21]

Answer: auxiliary

Explanation: got it right

7 0
2 years ago
C++A palindrome is a string such as "madam", "radar", "Dad", and "I", that reads the same forwards and backwards. The empty stri
jeka57 [31]

Answer:

See explaination

Explanation:

#include <iostream>

#include<string.h>

using namespace std;

bool isPalindrome(string str, int lower, int upper){

if(str.length() == 0 || lower>=upper){

return true;

}

else{

if(str.at(lower) == str.at(upper)){

return isPalindrome(str,lower+1,upper-1);

}

else{

return false;

}

}

}

int main(){

string input;

cout<<"Enter string: ";

cin>>input;

if(isPalindrome(input,0,input.length()-1)){

cout<<input<<" is a palindrome"<<endl;

}

else{

cout<<input<<" is NOT a palindrome"<<endl;

}

return 0;

}

5 0
2 years ago
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