Answer:
Option e)
Explanation:
Dimensional Analysis helps in the analysis of relationship between physical quantities, checking its dimension thus checking the accuracy of a given or to find the dimensions of a quantity or the degree of correctness of an equation.
Dimensional analysis has some of the applications that are listed below:
- To establish a relationship between physical quantities
- To check the accuracy of a given formula
- To derive units of a physical quantity
- To convert system of units in one another.
The radius of the specimen is 60 mm
<u>Explanation:</u>
Given-
Length, L = 60 mm
Elongated length, l = 10.8 mm
Load, F = 50,000 N
radius, r = ?
We are supposed to calculate the radius of a cylindrical brass specimen in order to produce an elongation of 10.8 mm when a load of 50,000 N is applied. It is necessary to compute the strain corresponding to this
elongation using Equation:
ε = Δl / l₀
ε = 10.8 / 60
ε = 0.18
We know,
σ = F / A
Where A = πr²
According to the stress-strain curve of brass alloy,
σ = 440 MPa
Thus,
Therefore, the radius of the specimen is 60 mm
Answer:
A degree in architecture with 60 credit hours.
Explanation:
The requirements need for a student to qualify for a two year master of architecture degree are;
- 60 credit hours in architecture
- Complete 60 credit hours in related area of profession such as; planning, landscape architecture ,public health and others.
- 45 credit hours in architecture course at the level of 500/600
Answer:
Combination circuit; The basic strategy for the analysis of combination circuits involves using the meaning of equivalent resistance for parallel branches to transform the combination circuit into a series circuit.
Example:
The use of both series and parallel connections within the same circuit. In this case, light bulbs A and B are connected by parallel connections and light bulbs C and D are connected by series connections. This is an example of a combination circuit.
Answer:
(a) 120 kW
(b) 800 kW
Explanation:
Given:
diameter: 1.5 m
length = 22 m
U = 5 m/s
temperature = 20°C
For water at 20°C, take ρ = 998 kg/m³ and µ = 0.001 kg/m⋅s
To find:
power in kW
(a) if the cylinder is parallel
Length / Diameter = L / D = 22 / 1.5 = 14.6 = 15
Re(L) = ρ*U*L / µ = 998 * 5 * 22 / 0.001 = 109780000 = 1.1E8
C(D.Frontal) ≈ 1.1
Force = F = 1.1 * ρ/2 * U² * π / 4 * D
= 1.1 (998 / 2) (5)²(π / 4)(1.5)²
= 1.1 * 499 * 25 * 0.785 * 2.25
= 24000 N
Power = Force * Displacement / time
= F * U
= 24000 * 5
= 120000
Power = 120 kW
b) if the cylinder is normal to the tow direction.
Re(L) = ρ*U*D / µ = 998 * 5 * 1.5 / 0.001 = 7485000 = 7.5E6
C(D.Frontal) ≈ 0.4
Force = F = 0.4 * ρ/2 * U² * D * L
= 0.4 (998 / 2) (5)²(1.5)(22)
= 164670 ≈ 165000
Power = Force * Displacement / time
= F * U
= 165000 * 5 = 825000
≈ 800 kW
Power = 800 kW
