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o-na [289]
2 years ago
14

) A certain polymer is used for evacuation systems for aircraft. It is important that the polymer be resistant to the aging proc

ess. Twenty specimens of the polymer were used in an experiment. Ten were assigned randomly to be exposed to an accelerated batch aging process that involved exposure to high temperatures for 10 days. Measurements of tensile strength of the specimens were made, and the following data were recorded on tensile strength in psi:
No aging: 227, 222, 218, 217, 225, 218, 216, 229, 228, 221
Aging: 219, 214, 215, 211, 209, 218, 203, 204, 201, 205

(a) Do a dot plot of the data.
(b) From your plot, does it appear as if the aging process has had an effect on the tensile strength of this polymer? Explain.
(c) Calculate the sample mean tensile strength of the two samples.
(d) Calculate the median for both. Discuss the similarity or lack of similarity between the mean and median of each group.
(e) Calculate the sample variance as well as standard deviation in tensile strength for both samples.
(f) Does there appear to be any evidence that aging affects the variability in tensile strength?
Engineering
1 answer:
bonufazy [111]2 years ago
5 0

Answer:

it will be a scattered plot

Explanation:

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Nơi nào có điện tích thì xung quanh điện tích đó có :
maksim [4K]

Explanation:

sory sorry sorry sorrysorrysorry

4 0
3 years ago
5. Which of the following is false about onStep?
katovenus [111]

The false statement about onStep is: B. The default number of steps per second is 30.

<h3>What is an onStep?</h3>

An onStep can be defined as a computerized telescope goto controller that is designed and developed to <u>animate shapes</u> while using it on a variety of mounting systems such as forks.

<h3>The characteristics of an onStep.</h3>

In Engineering, some of the characteristics that are associated with an onStep include the following:

  • The onStep function can be called without user input.
  • It can be used to animate shapes without user input.
  • It only runs a certain number of times.

In conclusion, the default number of steps per second for onStep isn't 30.

Read more on onStep here: brainly.com/question/25619349

7 0
2 years ago
What is the output of a system with the transfer function s/(s + 3)^2 and subject to a unit step input at time t = 0?
Dominik [7]

Answer:

0

Explanation:

output =transfer function H(s) ×input U(s)

here H(s)=\frac{s}{(s+3)^2}

U(s)=\frac{1}{s} for unit step function

output =H(s)×U(s)

=\frac{s}{(s+3)^2}×\frac{1}{s}

=\frac{1}{(s+3)^2}

taking inverse laplace of output

output=t×e^{-3t}

at t=0 putting the value of t=0 in output

output =0

3 0
4 years ago
(d) Arches NP is known for its spectacular arches that develop in the jointed areas of the park. Placemark Problem 2d flies you
Whitepunk [10]

Answer:

☐ NE-SW

Explanation:

Based on the description, the rock direction is North East - South West (NE-SW). Rocks generally can expand or compress depending on the type and magnitude of stress applied on the rocks. However, if the applied stress is sufficiently high, cracks and fractures will be created on the rock and it can ultimately lead to the formation of particles.

8 0
3 years ago
Suppose that you can throw a projectile at a large enough v0 so that it can hit a target a distance R downrange. Given that you
viktelen [127]

Answer:

\theta_1=15^o\\\theta_2=75^o

Explanation:

<u>Projectile Motion</u>

In projectile motion, there are two separate components of the acceleration, velocity and displacement. The horizontal component has zero acceleration (assuming no friction), and the acceleration in the vertical direction is always the acceleration of gravity. The basic formulas are shown below:

V_x=V_{ox}=V_ocos\theta

Where \theta is the angle of launch respect to the positive horizontal direction and Vo is the initial speed.

V_y=V_{oy}-gt=V_osin\theta-gt

The  horizontal and vertical distances are, respectively:

x=V_{o}cos\theta t

\displaystyle y=y_o+V_{o}sin\theta t-\frac{gt^2}{2}

The total flight time can be found as that when y = 0, i.e. when the object comes back to ground (or launch) level. From the above equation we find

\displaystyle t_f=\frac{2V_osin\theta}{g}

Using this time in the horizontal distance, we find the Range or maximum horizontal distance:

\displaystyle R=\frac{V_o^2sin2\theta}{g}

Let's solve for \theta

\displaystyle sin2\theta=\frac{R.g}{V_o^2}

This is the general expression to determine the angles at which the projectile can be launched to hit the target. Recall the angle can have to values for fixed positive values of its sine:

\displaystyle \theta_1=\frac{asin\left(\frac{R.g}{V_o^2}\right)}{2}

\displaystyle \theta_2=\frac{180^o-asin\left(\frac{R.g}{V_o^2}\right)}{2}

Or equivalently:

\theta_2=90^o-\theta_1

Given Vo=37 m/s and R=70 m

\displaystyle \theta_1=\frac{asin\left(\frac{70\times 9.8}{37^2}\right)}{2}

\theta_1=15^o

And

\theta_2=90^o-15^o=75^o

5 0
3 years ago
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