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3 years ago

What is the mean absolute deviation of the following data set 3, 13, 11, 5

Mathematics

1 answer:

charle [14.2K]3 years ago

6 0

Answer:

Step-by-step explanation:

Add up your data. 3+13+11+5=32
Divide the sum by the number of data you have. In your case you would divide 32/4/
This will give you 8, which is your mean. Now, subtract 8 from each value and put the difference to its absolute value.
Now, add up each of these values (5+5+3+3=16), then divide by 4. This will give you an answer of 4.

Hope this helps! Have a great day :)

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Choose the correct symbol to form a true statement. 11/18 ____5/9

Alinara [238K]

For this case we have the following numbers:

$\frac {11} {18} = 0.611111111111\\\frac {5} {9} = 0,555555555556$

Note that $\frac {11} {18}$ is greater than $\frac {5} {9},$ so the inequality sign must be placed with the opening towards $\frac {11} {18}$ .

Answer:

$\frac {11} {18}> \frac {5} {9}$

8 0

4 years ago

Help, thank you!

kaheart [24]

Answer:

√357

Step-by-step explanation:

multiply all three numbers together and since 357 cannot be simplified it stays as a radical

8 0

4 years ago

The mean number of words per minute (WPM) read by sixth graders is 84 with a standard deviation of 15 WPM. If 188 sixth graders

Anna007 [38]

Answer:

0.1836 = 18.36% probability that the sample mean would differ from the population mean by greater than 1.46 WPM

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The mean number of words per minute (WPM) read by sixth graders is 84 with a standard deviation of 15 WPM.

This means that $\mu = 84, \sigma = 15$

Sample of 188

This means that $n = 188, s = \frac{15}{\sqrt{188}}$

What is the probability that the sample mean would differ from the population mean by greater than 1.46 WPM?

Greater than 84 + 1.46 = 85.46 or less than 84 - 1.46 = 82.54. Since the normal distribution is symmetric, these probabilities are equal, so we find one of them and multiply by 2.

Probability is is less than 82.54.

P-value of Z when X = 82.54. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$