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joja [24]
3 years ago
9

A passenger train travels 392 mi in the same time that it takes a freight train to travel 322 mi. If the passenger train travels

20 mi/h faster than the freight train, find the speed of each train.
Physics
1 answer:
Yuri [45]3 years ago
6 0

Answer:

Explanation:

Given

distance traveled by  Passenger train is d_1=392\ mi

distance traveled by  Freight train is d_2=322\ mi

Both take same time to travel

suppose speed of freight train is x mph

so speed of passenger train is 20+x mph

we know time=\frac{distance}{speed}

t=\frac{392}{20+x}=\frac{322}{x}

392x=322x+322\times 20

70x=322\times 20

x=92\ mph

speed of passenger train x+20=112\ mph  

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The kinetic energy of a 10 Kg ball rolling at 10 meters per second is how many joules
Ulleksa [173]

Answer: 500 joules

Explanation:

Given that

Mass of ball = 10kg

kinetic energy = ?

velocity of the ball = 10m/s

Kinetic energy is the energy possessed by a moving object. It is measured in joules, and depends on the mass (m) of the object and the velocity (v) by which it moves

i.e K.E = 1/2mv²

K.E = 1/2 x 10kg x (10m/s)²

K.E = 0.5 x 10kg x (10m/s)²

K.E = 5 x 100

K.E = 500 joules

Thus, the kinetic energy of the ball is 500 joules

6 0
3 years ago
Please help me with this question
ladessa [460]

Answer:

conduction

Explanation:

5 0
3 years ago
Read 2 more answers
A 94 g particle undergoes SHM with an amplitude of 8.3 mm, a maximum acceleration of magnitude 7.8 x 103 m/s2, and an unknown ph
Lelechka [254]

Answer:

a) T = 6.49*10^-3 s

b) v = 8 m/s

c) E = 3 J

d) F = 733 N

e) F = 366.5 J

Explanation:

Given

Mass of particle, m = 94 g = 0.094 kg

Amplitude of the particle, A = 8.3 mm = 8.3*10^-3 m

Maximum acceleration of particle, a = 7.8*10^3 m/s²

the equation describing Simple Harmonic Motion is given as

x = A cos (wt +φ)

To fond the acceleration of this relationship, we would have to integrate. Twice, the first would be a Velocity, and the second acceleration that we need.

Velocity = dx/dt = -Aw sin(wt + φ)

Acceleration = d²x/dt = -Aw² cos(wt + φ)

From the question, we were given, magnitude of acceleration to be 7.8*10^3 m/s²

Aw² = 7.8*10^3

w² = 7.8*10^3 / A

w² = 7.8*10^3 / 8.3*10^-3

w² = 939759

w = √939759

w = 969

Recall, T = 2π/w, so that

T = (2 * 3.142) / 969

T = 6.49*10^-3 s

Maximum speed = Aw

Maximum speed = 8.3*10^-3 * 969

Maximum speed = 8.0 m/s

Total mechanical energy oscillator =

mgx + 1/2mx² =

1/2mv(max)² =

1/2 * 0.094 * 8² =

3 J

Maximum displacement

x = A cos(wt + φ)

For x to be maximum here, then cos(wt + φ) Must be equal to 1

Acceleration = d²x/dt² = -Aw²

And force = mass * acceleration

Force = 0.094 * 7.8*10^3

Force = 733 N

x = A cos(wt + φ), where cos(wt + φ) = 1/2

d²x/dt² = -Aw² * 1/2

d²x/dt² = 733 * 0.5

= 366.5 N

7 0
3 years ago
1. What is the arrangement of the outer planets? 2. What effect does their placement have the planets?
Rasek [7]
<span>the arrangement of the outer planets is 
</span>1. Mercury 
<span>2. Venus </span>
<span>3. Earth </span>
<span>4. Mars </span>
<span>5. Jupiter </span>
<span>6. Saturn </span>
<span>7. Uranus </span>
8. Neptune
the inner most of the outer plannets is jupitor it is followed by saturn uranus and neptune
4 0
3 years ago
Help please 20 points ? ASAP
KengaRu [80]

Answer:

21: Mass

22: Unbalanced Force

23: Friction

24: Balanced

Explanation:

3 0
2 years ago
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