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sladkih [1.3K]
3 years ago
5

How many moles are in 174g of NaCL?

Chemistry
2 answers:
Misha Larkins [42]3 years ago
5 0

Answer:

58.44277 grams

Explanation:

Im in middle school and I know this! LOL

makvit [3.9K]3 years ago
3 0

FISH BOWL REAL IT IN ITZ ME AND MY FREIND GO BUDD WORK WORK. LOLLLLLL

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If you add the same amount of heat to two different substances, will they both change phase?
lesantik [10]

Answer:

It depends on their melting and/or their boiling points, because the heat provides the particles with kinetic energy to break the electrosatic bonds in the substances, which can differ in strength

Explanation:

8 0
2 years ago
Try to rationalize the sign of ΔS∘rxn in each case.
bonufazy [111]

Answer:

a) decrease, gas

b) increase, gas

c) liquid

d) increase, solid

Explanation:

Entropy refers to the degree of disorderliness of a system. If the number of moles of gas increases from left to right in a reaction, the entropy of the system increases positively.

Similarly, when the number of liquid molecules remain constant, there could only be a very little increase in entropy.

However, solids have the least entropy and the entropy of a system decreases when a system yields solid products.

6 0
3 years ago
It is acceptable to use the seat belt and shoulder harness to secure both the passenger and the wheelchair?
DedPeter [7]
Suuurre...

If you want to die!!


3 0
3 years ago
A gas occupies 3.5L at 2.5 kPa pressure. What is the volume at 100 mmHg at the same temperature? Be sure to
nasty-shy [4]

The volume at 100 mmHg : 0.656 L

<h3>Further explanation</h3>

Boyle's Law  

<em>At a constant temperature, the gas volume is inversely proportional to the pressure applied  </em>

\rm p_1V_1=p_2.V_2\\\\\dfrac{p_1}{p_2}=\dfrac{V_2}{V_1}

V₁=3.5 L

P₁=2.5 kPa=18,7515 mmHg

P₂=100 mmHg

\tt \dfrac{18.7515}{100}=\dfrac{V_2}{3.5}\\\\V_2=\dfrac{18.7515\times 3.5}{100}=0.656~L

4 0
3 years ago
What mass of natural gas (CH4) must you burn to emit 264 kJ of heat?
mariarad [96]
The heat released by cpmolete the combustion of organic products with oxygen is called heat of combustion.

Here 1 mol of CH4 realesed 802.3 KJ

To emit 264 kJ you multiply you need (1 mol of CH4/802.3 kJ)* 264 kJ = 0.329 mol of CH4

The molar mass, MM, of CH4 is 12 g/mol + 4*1g/mol = 16 g/mol

The to obtain the mass multiply the number of moles times the molar mass:

mass = n * MM = 0.329mol * 16g/mol = 5.26 grams

Answer: 5.26 grams



7 0
2 years ago
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