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Lisa [10]
2 years ago
6

Anything i could add guys?

Chemistry
1 answer:
vampirchik [111]2 years ago
4 0

Answer:ur needed to gorw up

Explanation:seroiuslsitlty

Ya such me yaar

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Consider the equation below. Upper C a upper C upper O subscript 3 (s) double-headed arrow upper C a upper O (s) plus upper C up
stiks02 [169]

Answer:K subscript e q equals StartFraction StartBracket upper C upper O subscript 2 EndBracket StartBracket upper C a upper O EndBracket over StartBracket upper C a upper C upper O subscript 3 EndBracket EndFraction

Explanation: the answer has it's root in Law of mass action which states that; the rate of a chemical reaction is directly proportional to the product of the concentrations of the reactants raised to their respective stoichiometric coefficients.

8 0
3 years ago
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Abbreviation for mole
Sedbober [7]

Answer:

Maybe mol

Explanation:

6 0
3 years ago
A certain substance X has a normal freezing point of -6.4 C and a molal freezing point depression constant Kf= 3.96 degrees C.kg
Brut [27]

Answer:  1.0\times 10^2g

Explanation:

Depression in freezing point is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=T_f^0-T_f=(-6.4-(13.6))^0C=7.2^0C = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte like urea)

K_f = freezing point constant = 3.96^0C/m

m= molality

\Delta T_f=i\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}}\times \text{weight of solvent in kg}}

Weight of solvent (X)= 950 g = 0.95 kg  

Molar mass of non electrolyte (urea) = 60.06 g/mol

Mass of non electrolyte (urea) added = ?

7.2=1\times 3.96\times \frac{xg}{60.06 g/mol\times 0.95kg}

x=1.0\times 10^2g

Thus 1.0\times 10^2g urea was dissolved.

8 0
3 years ago
When being transferred from one container to another, liquids will
RoseWind [281]
A. I’m not positive but I’m pretty sure
7 0
2 years ago
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What is the partial pressure of radon if the total pressure is 780 torr and the
Brilliant_brown [7]

Answer:

0.03atm

Explanation:

Given parameters:

Total pressure  = 780torr

Partial pressure of water vapor  = 1.0atm

Unknown:

Partial pressure of radon  = ?

Solution:

A sound knowledge of Dalton's law of partial pressure will help solve this problem.

The law states that "the total pressure of a mixture of gases is equal to the sum of the partial pressures of the constituent gases".

Mathematically;

           P_{t}   =   P_{1}  + P_{2}   +   P_{n}

Since the total pressure is 780torr, convert this to atm;

                       760torr = 1 atm

                       780torr  = \frac{780}{760} atm  = 1.03atm

     For this problem;

Total pressure  = Partial pressure of radon + Partial pressure of water vapor

            1.03 = Partial pressure of radon + 1.0

  Partial pressure of radon  = 1.03 - 1.00  = 0.03atm

6 0
3 years ago
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