Answer: 
moles
Explanation:
According to avogadro's law, 1 mole of every substance weighs equal to molecular mass , occupies 22.4 L at STP and contains avogadro's number 
of particles.
To calculate the moles, we use the equation:
Given mass of ethanol = 0.2301
Molar mass of ethanol = 46.07 g/mol
Thus there are moles of ethanol are present in the sample.
A) Nitrogen has an ATOMIC mass number of 14, but nitrogen gas consists of N₂ molecules, so the mass to use in this problem is 28 g/mol. Rates of effusion ∝ 1/√(mass), so
<span>√(mass unknown) /√28 = (rate N₂ effusion)/(rate unknown effusion) = 1.59 </span>
<span>∴ mass unknown = (1.59)²(28) = 70.78 g/mol </span>
<span>B) One possible gas that comes close for this mass is NF₃.</span>
Answer:
See explanation
Explanation:
I know that we usually associate the sp3 hybridization to the tetrahedral shape. This is common in molecules such as CH4. So it may sound somewhat strange that NH3 molecule has an sp3 hybridized nitrogen atom and a trigonal pyramidal geometry.
Let us recall that the central nitrogen atom in NH3 has a lone pair of electrons. These lone pairs causes more repulsion than bond pairs. As a result of the presence of this lone pair, the bond angle in the NH3 molecule is distorted away from the expected 109.7 degrees in tetrahedral geometry and the bonding groups are now arranged in a trigonal pyramidal geometry(with bond angle less than 109.7 degrees) to minimize electron pair repulsions.
It is made of liquidy molten iron that is very hot.
Hello!
When aqueous solutions of Li₂SO₄ and NaI are mixed the following reaction occurs:
Li₂SO₄(aq) + 2NaI(aq) → 2LiI(aq) + Na₂SO₄(aq)
The compounds produced from this reaction are all soluble, so no precipitate is formed. We know that those compounds (LiI and Na₂SO₄) are soluble because of the solubility rules which states that salts from Group I elements (Li⁺, Na⁺) are soluble.
Have a nice day!
