Answer:
<span>As the temperature of a liquid solvent increases, the amount of solute that can dissolve in it <u>increases</u>.
Explanation:
The solubility of most solutes in a solvent increases with increase in temperature. This solubility is closely related to the heat of solution, (the heat evolved or absorbed when solute is dissolved in solvent). Hence, majority of solutes when dissolved in solvent absorbs heat and makes the overall heat of solution positive. Hence, in this case more heat provided will increase the rate of solubility.</span>
C:change in the earth's orbit correlate to changes in climate.
Over 344.76 K the forward reaction will be spontaneous
<u><em>calculation</em></u>
ΔG = ΔH° -TΔs
if ΔG =0
therefore 0 =ΔH°-TΔs
ΔH° = TΔs
divide both side by Δs
T = ΔH°/Δs
convert 34.2 kj into j
that is 1 kj = 1000 j
34.2 kj =? j
<em>by cross multiplication</em>
=[34.2 kj x 1000j / 1 kj] = 34200 j
T is therefore = 34200 j÷99.2 j/k =344.76 k
if T is greater than 344.76 k the forward reaction will be spontaneous
First determine the molality of the solution. m = (w solute)/[(mm solute)(kg solvent)] -- mm means molar mass. So,
m = (14.7 g)/[(180 g/mol)(0.150 kg) =0.544 mol/kg = 0.544 m
Change in boiling point (∆t) = m x Kbp = (0.544 m)(0.512 °C/m) = 0.28°C
The solution will boil at 100.28°C at 1 atm.
the density if water is 1.00 g/ml and Kb= 0.512 C/m
M(Ag)=12.5 g
Nₐ=6.022*10²³ mol⁻¹
n(Ag)=m(Ag)/M(Ag)
N=n(Ag)*Nₐ
N=Nₐm(Ag)/M(Ag)
N=6.022*10²³mol⁻¹*12.5g/107.868g/mol=6.97*10²²
A. 6.97 × 10²² atoms
