The polynomial function with the given properties is; y = 2(x - 3)³(x + 4)²
<h3>How to construct polynomial functions?</h3>
Polynomials are defined as algebraic expressions that consist of variables, coefficients, and constants. The standard form of polynomials has mathematical operations such as addition, subtraction, and multiplication.
We need to form a polynomial expression with the following properties;
fifth-degree, 3 is a zero of multiplicity 3, −4 is the only other zero and ,the leading coefficient is 3. Thus, the polynomial will be;
y = 2(x - 3)³(x + 4)²
Read more about Polynomial functions at; brainly.com/question/7693326
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If you are finding X it equals 3
Answer:
Find Radius using distance formula.
![radius = \sqrt{(8 -- 7)^2 +(7--1)^2} \\](https://tex.z-dn.net/?f=radius%20%3D%20%5Csqrt%7B%288%20--%207%29%5E2%20%2B%287--1%29%5E2%7D%20%5C%5C)
=![\sqrt{15^2 + 8^2} = \sqrt{225 + 64 } =\sqrt{289} = 17 units](https://tex.z-dn.net/?f=%5Csqrt%7B15%5E2%20%2B%208%5E2%7D%20%3D%20%5Csqrt%7B225%20%2B%2064%20%7D%20%20%3D%5Csqrt%7B289%7D%20%3D%2017%20units)
Since the point (-15, y) lies on the circle. The distance between (-7, -1) and
(-15, y ) will be 17 units.
So again using distance formula we will find y.
![radius = \sqrt{(-7 --15)^2 + (-1-y)^2} \\\\17 = \sqrt{8^2 + (y+1)^2}\\\\squaring \ both \ sides \\\\289 = 64 + (y+1)^2\\\\289-64=(y+1)^2\\\\225 = (y+1)^2\\\\taking \ squaring \ root\\\\15 = y+1\\\\y=14](https://tex.z-dn.net/?f=radius%20%3D%20%5Csqrt%7B%28-7%20--15%29%5E2%20%2B%20%28-1-y%29%5E2%7D%20%5C%5C%5C%5C17%20%3D%20%5Csqrt%7B8%5E2%20%2B%20%28y%2B1%29%5E2%7D%5C%5C%5C%5Csquaring%20%5C%20both%20%5C%20sides%20%5C%5C%5C%5C289%20%3D%2064%20%2B%20%28y%2B1%29%5E2%5C%5C%5C%5C289-64%3D%28y%2B1%29%5E2%5C%5C%5C%5C225%20%3D%20%28y%2B1%29%5E2%5C%5C%5C%5Ctaking%20%5C%20squaring%20%5C%20root%5C%5C%5C%5C15%20%3D%20y%2B1%5C%5C%5C%5Cy%3D14)
point (-15, 14)
Answer:
![\huge \boxed{G=-65}\checkmark](https://tex.z-dn.net/?f=%5Chuge%20%5Cboxed%7BG%3D-65%7D%5Ccheckmark)
Step-by-step explanation:
First, you multiply by 5 from both sides of equation.
![\displaystyle \frac{5g}{5}=5(-13)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B5g%7D%7B5%7D%3D5%28-13%29)
Simplify, to find the answer.
![\displaystyle 5(-13)=-65](https://tex.z-dn.net/?f=%5Cdisplaystyle%205%28-13%29%3D-65)
, which is our answer.