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babymother [125]

3 years ago

9

how many solutions does each system of equation have?? explain how you know without solving the system

1 answer:

Leto [7]3 years ago

8 0

Answer:

no solution

Step-by-step explanation:

the x value in a linear equation in slope intercept form represents the slope of the line, since both equations int the system have the same slope there is no solution.

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Write 2% as a reduced fraction

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2% as a reduced fraction is 2/100 = 1/50

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What is 72% as a fraction

PSYCHO15rus [73]

72% as a fraction is 18/25.

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4 years ago

Factor completely 4x2 − 8x + 4.

olga nikolaevna [1]

<u>Given </u><u>:</u><u>-</u><u> </u>

4x² - 8x - 4 .

<u>To </u><u>Find</u><u> </u><u>:</u><u>-</u><u> </u>

To find the factorised form .

<u>Answer</u><u> </u><u>:</u><u>-</u><u> </u>

Taking the given expression,

→ 4x² - 8x + 4

→ 4x² - 4x -4x + 4

→ 4x ( x - 1 ) -4( x -1)

→ (4x - 4)(x-1)

<u>Hence </u><u>the</u><u> </u><u>required</u><u> answer</u><u> is</u><u> </u><u>(</u><u>4</u><u>x</u><u> </u><u>-</u><u> </u><u>4</u><u>)</u><u>(</u><u> </u><u>x </u><u>-</u><u> </u><u>1</u><u>)</u><u> </u><u>.</u>

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3 years ago

How much does 48 ounces of spring fresh water cost ?

kogti [31]

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4 years ago

Involving the selection of frozen dinners. Assume that there are 15 frozen dinners: 7 pasta, 6 chicken, and 2 seafood dinners. T

zzz [600]

The probability that at least 2 of the dinners selected are pasta dinners will be 0.8181...

<u><em>Explanation</em></u>

Pasta dinners = 7 , Chicken dinners = 6 and Seafood dinners = 2

The student selects 5 of the total 15 dinners. So, total possible ways for selecting 5 dinners $=^1^5C_{5} =3003$

For selecting at least 2 of them as pasta dinners, the student can select 2, 3, 4 and 5 pasta dinners from total 7 pasta dinners.

So, the possible ways for selecting 2 pasta dinners $=^7C_{2}*^8C_{3} =1176$

The possible ways for selecting 3 pasta dinners $=^7C_{3}*^8C_{2} =980$

The possible ways for selecting 4 pasta dinners $=^7C_{4}*^8C_{1} =280$

The possible ways for selecting 5 pasta dinners $=^7C_{5}*^8C_{0} =21$

Thus, the probability for selecting at least 2 pasta dinners $=\frac{1176+980+280+21}{3003} =\frac{2457}{3003} =0.8181.....$

3 0

4 years ago