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eduard
3 years ago
12

Formulae for covalent compounds

Chemistry
2 answers:
frutty [35]3 years ago
7 0

Answer:

The answers is PI3

Explanation:

Cause i said so

Margarita [4]3 years ago
6 0

Answer:

plz answer my question i dont know what to dohtt

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What is 2H2 + O2 2H2O in oxidation form and in reduction form?
Eva8 [605]

In the reaction of water, 2H2 is oxidized to form 2H2O by gaining oxygen atom which shows that 2H2 is reducing agent as it undergoes oxidation.

<h3>What is reducing agent?</h3>

A reducing agent is a type of chemical that "donates" an electron to another atom that needs an electron. This type of reaction in which loss of electron occurs is called reduction reaction.

So we can conclude that 2H2 is oxidized to form 2H2O by gaining oxygen atom which shows that 2H2 is reducing agent as it undergoes oxidation.

Learn more about reduction here: brainly.com/question/3457976

#SPJ1

7 0
2 years ago
100 points plus i'll mark brainliest
sdas [7]
I think the answer is 98 grams
5 0
3 years ago
How can you distinguish a clastic sedimentary rock from a crystalline formed sedimentary rock?
Ket [755]
:<span>  </span><span>A clastic sedimentary rock will be full of... clasts. Pieces of shells, ooids, pizoids, etc. A chemically formed sedimentary rock may have these but it will dominantly be a layered rock, you should be able to see concentric layers</span>
6 0
3 years ago
The reaction for producing glucose in plants, called photosynthesis, is 6 CO 2 + 6 H 2 O light −−→ C 6 H 12 O 6 + 6 O 2 6CO2+6H2
Nostrana [21]

Answer:

30.36moles

Explanation:

6CO2 + 6H2O → C6H12O6 + 6O2

From the equation above,

6moles of H2O are required to produce 1 mole of C6H12O6

Therefore, Xmol of H2O will be require to 5.06moles of C6H12O6 i.e

Xmol of H2O = 6 x 5.06 = 30.36moles

Therefore, 30.36moles of H2O are needed.

5 0
3 years ago
A 45.0 g block of an unknown metal is heated in a hot water bath to 100.0°c. when the block is placed in an insulated vessel con
professor190 [17]
Let's apply the principle of conservation of energy.

Heat of metal = Heat of water
mCmetalΔT = mCwaterΔT

Applying the given values,

(45 g)(Cmetal)(100 - 28 °C) = (130 g)(4.18 J/g-°C)(28 - 25 °C)
Solving for Cmetal,
<em>Cmetal = 0.503 J/g°C

Therefore, the heat capacity of the unknown metal is 0.503 J/g</em>
°C.
5 0
4 years ago
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