What groups are transitional metals in
Helium at room temperature is Gaseous
hope that helps
<span>The American Council for an Energy-Efficient Economy works to (c) </span>invest in clean energy technologies that will strengthen the economy.
Their aim is to promote energy efficiency which will ultimately benefit the economy and the environment.
Answer:
See the answer below
Explanation:
From the original equation in the image, the mole ratio of C:CO2:CO is 1:1:2. This means that for every 1 mole of C and CO2, 2 moles of CO would be produced.
Now, looking at the simulation below the equation of the reaction, 3 moles of C and 8 moles of CO2 were supplied as input. Applying this to the original equation of reaction, C seems to be a limiting reagent for the reaction because the ratio of C to CO2 should 1:1.
Hence, taking all the 3 moles of C available means that only 3 moles out of the available 8 for CO2 would be needed. 3 moles c and 3 moles CO2 means that 6 moles CO would be produced (remember that the ratio remains 1:1:3 for C, CO2, and CO). This means that 5 moles CO2 would be leftover.
<em>In other words, all the 3 moles C would be consumed, 3 out of 8 moles CO2 would be consumed, and 6 moles CO would be produced while 5 moles CO2 would be leftover. </em>
Answer:
108.9897 psi
Explanation:
Using Ideal gas equation for same mole of gas as
Given ,
Let V₁ = x units
The new volume increases by 4 % which means
V₂ = x + 0.04x = 1.04 x
P₁ = 100 psi
P₂ = ?
T₁ = 19 ºC
T₂ = 58 ºC
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T₁ = (19 + 273.15) K = 292.15 K
T₂ = (58 + 273.15) K = 331.15 K
Using above equation as:
Solving for P₂ , we get:
<u>P₂ = 108.9897 psi</u>