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3 years ago

Fill in the blanks to correctly describe each separation process.

Chemistry

1 answer:

Dimas [21]3 years ago

4 0

Answer:

C, B ,A(in the order of the blanks)

Explanation:

A centrifuge uses centrifugal force to seperate 2 substances with different densities, the lighter one at the top. This cannot be done with homogeneous mixtures

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For the following reaction, 76.0 grams of barium chloride are allowed to react with 67.0 grams of potassium sulfate. barium chlo

Nataliya [291]

For the following reaction, 76.0 grams of barium chloride are allowed to react with 67.0 grams of potassium sulfate.

The reaction consumes _____ moles of barium chloride. The reaction produces _____ moles of barium sulfate and _____ moles of potassium chloride.

Answer: a) The reaction consumes 0.365 moles of barium chloride.

b) The reaction produces 0.365 moles of barium sulfate and 0.730 moles of potassium chloride.

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of barium chloride}=\frac{76.0}{208g/mol}=0.365moles$

$\text{Moles of potassium sulphate}=\frac{67.0}{174g/mol}=0.385moles$

$BaCl_2(aq)+K_2SO_4(aq)\rightarrow BaSO_4(s)+2KCl(aq)$

According to stoichiometry :

1 mole of $BaCl_2$ require 1 mole of $K_2SO_4$

Thus 0.365 moles of $BaCl_2$ will require= $\frac{1}{1}\times 0.365=0.365moles$ of $K_2SO_4$

Thus $BaCl_2$ is the limiting reagent as it limits the formation of product and $K_2SO_4$ is the excess reagent.

As 1 moles of $BaCl_2$ give = 1 moles of $BaSO_4$

Thus 0.365 moles of $BaCl_2$ give = $\frac{1}{1}\times 0.365=0.365moles$ of $BaSO_4$

As 1 moles of $BaCl_2$ give = 2 moles of $KCl$

Thus 0.365 moles of $BaCl_2$ give = $\frac{2}{1}\times 0.365=0.730moles$ of $KCl$

Thus the reaction consumes 0.365 moles of barium chloride. The reaction produces 0.365 moles of barium sulfate and 0.730 moles of potassium chloride.

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