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Umnica [9.8K]
3 years ago
5

Think about a hot summer afternoon at the beach

Chemistry
2 answers:
pentagon [3]3 years ago
4 0

Answer:

D

Explanation:

I say this because of this that I read. There was a study shown

"Our experiment was a success. We obtained data that answered our problem, “Which substance absorbs the most heat on a hot day? Sand, water, or sand with water?” The results showed that from the twenty-five trials: the cup of sand temperature ranged from 63-68°C, cup of water temperature ranged from 71-77°C, and the cup of sand with water temperature ranged from 66-71°C. Based on our data, our hypothesis was incorrect. We hypothesized that the sand would absorb the most heat since it is darker and less reflective than water; but from our data, water absorbed the most heat. In conclusion, sand absorbed the least amount of heat and water absorbed the most. Next time we want to cool down at the beach, we’ll know where to go!"

This was an experiment that was performed and this is the conclusion

Hope that helps

NeTakaya3 years ago
3 0
A. Would be the correct answer :-)
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To 0.360 l of 0.160 m nh3 is added 0.120 m mgcl2. how many grams of (nh4)2so4 should be present to prevent the precipitation of
vazorg [7]
<span> first calculate the moles of every compound used

n NH3 = (0.160 mol /L )(0 .360 L) = 0.058 moles NH3
which is equal to moles NH4OH
0.058 moles NH4OH.

  n MgCl2 = (0.12 mol /L)( 0.10 liters = .012 moles MgCl2

reaction 2 NH3.H20 or 2 NH4OH + MgCl2 --> Mg(OH)2(s) + 2 NH4+ + 2Cl-

Molarity of Mg++ =(0.012 moles Mg+) / 0.46 liters = 0.026 Molar Mg++

Molarity OH= (0.058 moles OH-)/ 0.46 liters = 0.126 molar OH-

the limiting reactant is Mg ++ because it is lesser than the molarity of OH-

Now the challenge is to drive the OH-) concentration down so low that Mg(OH)2 will not precipitate out.

Ksp = 1.8 x 10^-11 = (Mg)(OH-)^2

  Mg++ concentration to be .026 Molar, so let X = the (OH-) concentration

1.8 x l0^-11 = (0.026)(X)^2

(X)^2 = ( 1.8 x 10^-11) / (0.026)

X^2 = 6.92 x 10^-10
X = 2.63 x l0^-5 moles (OH-)/ L
this is the concentration where solid will form

so we need to lower the (OH-) which is 0.126 molar OH- down to 2.63 x 10^-5 molar OH- by adding NH4+ ions.

(0.126 moles/liter 0H-) - (2.63 x l0^-5 molar OH- ) = 0.123 moles per liter

OH- to be neutralized by adding NH4+

since the mole ratio is 1 : 1 then </span><span> 0.123 moles per liter NH4+ concentration to neutralize the </span><span><span> 0.123</span> moles of OH- in solution.


so to prevent the precipitation of mg(oh)2

0.123 - 0.058 = 0.065 Molar NH4+ is needed

</span>
5 0
4 years ago
How does hardness affect the rate of weathering in a rock?
tamaranim1 [39]

Explanation:

Hardness of rocks makes weathering difficult and not easy to come by.

Weathering is the physical disintegration and chemical decomposition of rocks to form sediment and soils.

The agents of weathering are primarily the agents of denudation which are wind, rainfall, glacier, gravity and temperature.

  • Most igneous and metamorphic rocks are usually termed hard rocks.
  • Sedimentary rocks typically falls into the category of soft rocks.
  • Hard rocks are more compact and have their crystals woven into one another.
  • It takes a longer time for them to get weathered.
  • Soft rocks are often times bounded by cements.
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Therefore, the harder a rock is, the more time it takes for it to be disintegrated.

Learn more:

Sedimentary process brainly.com/question/9131992

#learnwithBrainly

6 0
4 years ago
The Mass of the paper before being bumed is 50% how much mass should there be after
neonofarm [45]

0%

Explanation:

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3 0
2 years ago
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The number of moles of Al, S, and O atoms are 18, 27 and 108.

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