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Novosadov [1.4K]
3 years ago
9

8. Quelles sont les deux conditions afin que deux vivants appartiennent à la même espèce?

Chemistry
1 answer:
telo118 [61]3 years ago
4 0
À des Se reproduire entre eux petits viables des petits 3 Les descendants doivent reproduire avec succès. et donner naissance qui peuvent surviure
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How many grams of solute are present in 1250 mL of a 1.34 M NaNO3 solution?
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He answer is 42 because you carry the one
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Help me to balance this equations pls!<br> C3H8 02 CO+H20<br> Thank you
vichka [17]

Answer:

2C3H8 402 6CO+8H20

Explanation:

8 0
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How to make Sodium thiosulfate
Arada [10]

Explanation:

Method of prepration of sodium thiosulphate - definition

In the laboratory, this salt can be prepared by heating an aqueous solution of sodium sulphite with sulphur or by boiling aqueous NaOH and sulfur according to this equation:

6NaOH + 4 S _{2} Na _{2} S ->Na _{2} S_{2}O_{3}+ 3H _{2}O.

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3 years ago
For most substances,the distance between particles is furthest when the substance is?
valentinak56 [21]
Im not positive but i think it is When it is a gas?
3 0
3 years ago
At a pressure of 650 kpa 2.2L of hydrogen is used to fill a balloon to a final pressure of 115 kpa. What's the balloons volume?
Alborosie

Answer:

V₂ = 12.43 L

Explanation:

Given data:

Initial pressure = 650 KPa

Initial volume = 2.2 L

Final pressure = 115 KPa

Final volume = ?

Solution:

The given problem will be solved through the Boyles law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

650 KPa ×2.2 L = 115 KPa × V₂

V₂ = 1430 KPa. L/ 115 KPa

V₂ = 12.43 L

4 0
3 years ago
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