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Bezzdna [24]
3 years ago
14

Explain why salivary amylase would not digest protein

Chemistry
1 answer:
CaHeK987 [17]3 years ago
6 0

Answer:This particular enzyme promotes the breakdown of starches into simpler sugars which can be absorbed by the body. Salivary amylase, like most other enzymes, is a protein. ... Consequentlysalivary amylase does not function once it enters the stomach.

Explanation:

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Daniel is conducting an experiment on magnetic objects. He completes more than one trial. Why is it important for Daniel to do t
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Answer:The conclusion is less accurate.

Explanation:

Feb 17, 2021 — He completes more than one trial. Why is it important for Daniel to do this?

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Huge loops of plasma erupting from the sun are called.
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magnetic Flux ropes

Explanation:

Magnetic flux ropes (also known as coronal loops and solar prominences) sit on the surface of the sun, with matter and energy flowing through them, for hours or days.

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2 years ago
Which of the following is formed when an acid reacts with a base? Alkaline Hydrogen ion Hydroxide ion Salt
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Salt (not table salt!) is formed when an acid reacts with a base. Salt is a compound. Water is also produced as a by-product of this reaction.
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2 years ago
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Please help, I will love you for life!!
vichka [17]
Here's what I got. Hope it helps.

5 0
3 years ago
At 298 K, the rate constant for a reaction is 0.0346 s-1. What is the rate constant at 350K if the Ea = 50.2kJ/mol
frutty [35]

Answer:

0.702 /s

Explanation:

Rate constant at [298 \mathrm{~K}, \mathrm{~K}_{1}=3.46 \times 10^{-2} \mathrm{~s}^{-1}

Rate constant at 350 \mathrm{~K}, \mathrm{~K}_{2}=?

T_{1}=298 \mathrm{~K}

T_{2}=350 \mathrm{~K}

Activation energy, \mathrm{Ea}=50.2 \times 10^{3} \mathrm{~J} / \mathrm{mol}

Use the following equation to calculate K_{2}$ at $350 \mathrm{~K}

Use the following equation to calculate K_{2}$ at $350 \mathrm{~K}

\ln \frac{\mathrm{K}_{2}}{\mathrm{~K}_{1}}=\frac{\mathrm{Ea}}{\mathrm{R}}\left[\frac{1}{\mathrm{~T}_{1}}-\frac{1}{\mathrm{~T}_{2}}\right]

Therefore,

 \ln \left(\frac{K_{2}}{3.46 \times 10^{-2} \mathrm{~s}^{-1}}\right) &=\frac{50.2 \times 10^{3} \mathrm{~J} / \mathrm{mol}}{8.314 \mathrm{JK}^{-1} \mathrm{~mole}^{-1}}\left[\frac{1}{298 \mathrm{~K}}-\frac{1}{350 \mathrm{~K}}\right]

\ln \left(\frac{K_{2}}{3.46 \times 10^{-2} \mathrm{~s}^{-1}}\right) &=\frac{50.2 \times 10^{3} \mathrm{~J} / \mathrm{mol}}{8.314 \mathrm{JK}^{-1} \mathrm{~mole}^{-1}}\left[\frac{52 \mathrm{~K}}{298 \mathrm{~K} \times 350 \mathrm{~K}}\right]

\frac{K_{2}}{3.46 \times 10^{-2} \mathrm{~s}^{-1}} &=\mathrm{e}^{3.01}

\frac{K_{2}}{3.46 \times 10^{-2} \mathrm{~s}^{-1}} &=20.3

K_{2} &=20.3 \times 3.46 \times 10^{-2} \mathrm{~s}^{-1}

&=0.702 \mathrm{~s}^{-1}

hence, the rate constant at 350 \mathrm{~K} is 0.702\mathrm{~s}^{-1}

5 0
2 years ago
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