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kolbaska11 [484]
3 years ago
11

sperm cells use their tails to swim towards an ovum( egg). give one otherr way the sperm cell is adapted for fertilsation?

Chemistry
1 answer:
maxonik [38]3 years ago
4 0

Answer:

The sperm cell is adapted to its function in multiple ways:It has a tail which enables it to swim towards the egg

Explanation:

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6.00g of gold was heated from 20.0c to 22.0c. How much heat was applied to the gold
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6 x .129 x 2= 1.55J
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The half-life of radioactive substance is 2.5 minutes. what fraction of the origional radioactive remains after 10 mins
saul85 [17]
The answer is 1/16.

Half-life is the time required for the amount of a sample to half its value.
To calculate this, we will use the following formulas:
1. (1/2)^{n} = x,
where:
<span>n - a number of half-lives
</span>x - a remained fraction of a sample

2. t_{1/2} = \frac{t}{n}
where:
<span>t_{1/2} - half-life
</span>t - <span>total time elapsed
</span><span>n - a number of half-lives
</span>
So, we know:
t = 10 min
<span>t_{1/2} = 2.5 min

We need:
n = ?
x = ?
</span>
We could first use the second equation to calculate n:
<span>If:
t_{1/2} = \frac{t}{n},
</span>Then: 
n = \frac{t}{ t_{1/2} }
⇒ n = \frac{10 min}{2.5 min}
⇒ n=4<span>
</span>
Now we can use the first equation to calculate the remained fraction of the sample.
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3 0
3 years ago
How many Electrons, Neutrons &amp; Protons do
EastWind [94]

Answer:

sodium

protons:11

neutrons:12

electrons:11

nitrogen

protons:7

neutrons:7

electrons:7

6 0
3 years ago
Read 2 more answers
Who made the first periodic table
ale4655 [162]
The other dude is rude wrong

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8 0
3 years ago
In NMR if a chemical shift(δ) is 211.5 ppm from the tetramethylsilane (TMS) standard and the spectrometer frequency is 556 MHz,
Vika [28.1K]

Answer:

The answer is: 11759 Hz

Explanation:

Given: Chemical shift: δ = 211.5 ppm, Spectrometer frequency = 556 MHz = 556 × 10⁶ Hz

In NMR spectroscopy, the chemical shift (δ), expressed in ppm, of a given nucleus is given by the equation:

\delta (ppm) = \frac{Observed\,frequency (Hz)}{Frequency\,\, of\,\,the\,Spectrometer (MHz)} \times 10^{6}

\therefore Observed\,frequency (Hz)= \frac{\delta (ppm)\times Frequency\,\, of\,\,the\,Spectrometer (MHz)}{10^{6}}

Observed\,frequency= \frac{211.5 ppm \times 556 \times 10^{6} Hz}{10^{6}} = 11759 Hz

<u>Therefore, the signal is at 11759 Hz from the TMS.</u>

6 0
4 years ago
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