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Sholpan [36]
4 years ago
5

By the term universe astronomers mean

Physics
1 answer:
OverLord2011 [107]4 years ago
6 0

'Universe' means 'Everything'. That is, all matter, all space, all time.

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Pedro is building a model motor. He would like the motor to be more powerful. Which of the following would best help him increas
Ratling [72]

The answer is B because that that will make it more powerful but less lasting.

7 0
3 years ago
A 2.0 kg tumor is being irradiated by a radioactive source.The
navik [9.2K]

Answer:

426136363636.36365 Bq

Explanation:

Grays = 12

Mass = 2 kg

Time = 880

Energy = 0.4 MeV

Activity is given by

Activity=\dfrac{Grays\times Mass}{Time\times 0.4}\\\Rightarrow Activity=\dfrac{12\times 2}{880\times 0.4\times 1.6\times 10^{-13}}\\\Rightarrow Activity=426136363636.36365\ Bq

The activity N//t of the radioactive source is 426136363636.36365 Bq

6 0
4 years ago
Copper has a specific heat of 387 J/kg°C. A copper bullet is moving at 950 m/s. If the bullet is suddenly stopped so that all of
Alla [95]

Answer:

1196.02 °C

Explanation:

If the kinetic energy is converted into heat,

then,

Kinetic energy of the copper = heat energy of the copper

1/2m(v²) = cm(t₂-t₁)

where m = mass of copper, v =  velocity of copper, c = specific heat capacity of copper, t₂ = final temperature of copper, t₁ = initial temperature of copper.

Since the mass of copper remains the same,

1/2v² = c(t₂-t₁)

make t₂ the subject of the equation

t₂ = 1/2(v²/c)+t₁..................... Equation 1

Given: v = 950 m/s, c = 387 J/kg°C, t₁ 30 °C

Substitute into equation 1

t₂ = 1/2(950²/387)+30

t₂ = 1196.02 °C

Hence the temperature the bullet reach before it was stopped = 1196.02 °C

8 0
4 years ago
Which factor affects gravitational potential energy but not elastic potential energy?
Oksana_A [137]
Mass....................
3 0
4 years ago
Read 2 more answers
(1 point) Answer the following questions about the sphere whose equation is given by x2+y2+z2−4x+4y=73. x2+y2+z2−4x+4y=73. 1. Fi
pychu [463]

Answer:

R=9.

C=(2,-2,0).

Explanation:

Lets try to find how x^2+y^2+z^2-4x+4y=73 can be written in the form of (x-a)^2+(x-b)^2+(x-c)^2=R^2, since then its radius R and center of coordinates C=(a,b,c) would be easily recognizable.

Since we have the terms -4x and +4y, they seem to have come from the terms (x-2)^2 and (y+2)^2, and we would need to take care of the extra +4 by substracting then. More explicitly:

(x-2)^2-4=x^2-4x+4-4=x^2-4x, as we had originally with the x terms

(y+2)^2-4=y^2+4y+4-4=y^2+4y, as we had originally with the y terms

Which means:

x^2-4x+y^2+4y+z^2=(x-2)^2-4+(y+2)^2-4+z^2

Or, putting all together:

(x-2)^2-4+(y+2)^2-4+z^2=73

(x-2)^2+(y+2)^2+z^2=9^2

So our radius is 9 and the center is (2,-2,0).

5 0
3 years ago
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