Your answer is B. 1.53 m/s towards the beach.
110/72 = 1.52777 and then you round it to 1.53 :)
Answer:
The magnitude of the average induced emf in the wire during this time is 9.533 V.
Explanation:
Given that,
Radius r= 0.63 m
Magnetic field B= 0.219 T
Time t= 0.0572 s
We need to calculate the average induce emf in the wire during this time
Using formula of induce emf



.....(I)
In reshaping of wire, circumstance must remain same.
We calculate the length when wire is in two loops



The length when wire is in one loop




We need to calculate the initial area

Put the value into the formula


The final area is



Put the value of initial area and final area in the equation (I)


Negative sign shows the direction of induced emf.
Hence, The magnitude of the average induced emf in the wire during this time is 9.533 V.
Well, it is also known as the transmission of fluid pressure. So, it is a principle in fluid mechanics that says that pressure exerted anywhere in a confined incompressible fluid is transmitted equally in all directions throughout the fluid such as the the pressure variations.
Answer:
<h2>
work done= 48.96 kJ</h2>
Explanation:
Given data
mass of load m= 425 kg
height/distance h=64 m
acceleration a= 1.8 m/s^2
The work done can be calculated using the expression
work done= force* distance
but force= mass *acceleration
hence work done= 425*1.8*64= 48,960 J
work done= 48.96 kJ
Yes i think so!!!
i think..
your totally right Angi.