Oooo that ones hard. ummm... idk i think we should just leave it to the experts ya know.
Answer:
40479.6 J
Explanation:
Applying,
q = cm(t₂-t₁).................... Equation 1
Where q = change in heat content of the system, c = specific heat capacity of the system, m = mass of the system, t₁ = initial temperature, t₂ = final temperature.
From the question,
Given: m = 79 g = 0.079 kg, t₁ = 21°C, t₂ = 143°C
Constant: c = 4200 J/kg.°C
Substitute these values into equation 1
q = 4200(0.079)(143-21)
q = 331.8(122)
q = 40479.6 J
Answer:
Both are only physical changes
Explanation:
A physical change is a change that does not involve or alter the chemical composition of the substances involved. Physical changes form no new substance and can be easily separated into individual constituents. Example of physical changes are change in state, boiling, melting etc.
According to this question, two processes were given as follows:
1. mixing chocolate syrup into milk
2. rain forming in a cloud
These two processes are similar in the sense that they are both examples of physical changes.
A car is built from various subsystems. If these subsystems are not working properly it is dangerous because it can cause a serious traffic accident.
<h3>What subsystems do cars have?</h3>
When you're testing the build of a car, you have to check its many subsystems:
- the battery
- the engine
- the cabin
- the thermal-management system
- the gearbox
- the chassis
- the suspension
<h3>Why is a car with damaged subsystems dangerous?</h3>
The subsystems of a car are very important components that allow the proper functioning of the car. These subsystems work synchronously making the car work properly.
However, if one of these subsystems is not working properly it could cause a malfunction that could lead to a traffic accident.
Learn more about cars in: brainly.com/question/11733094
Answer:
that best describes the process is C
Explanation:
This problem is a calorimeter process where the heat given off by one body is equal to the heat absorbed by the other.
Heat absorbed by the smallest container
Q_c = m ce (
-T₀)
Heat released by the largest container is
Q_a = M ce (T_{i}-T_{f})
how
Q_c = Q_a
m (T_{f}-T₀) = M (T_{i} - T_{f})
Therefore, we see that the smaller container has less thermal energy and when placed in contact with the larger one, it absorbs part of the heat from it until the thermal energy of the two containers is the same.
Of the final statements, the one that best describes the process is C
since it talks about the thermal energy and the heat that is transferred in the process
