Answer:
1/9 of that just outside the smaller sphere
Explanation:
The electric field strength produced by a charged sphere outside the sphere itself is equal to that produced by a single point charge:

where
k is the Coulomb's constant
Q is the charge on the sphere
r is the distance from the centre of the sphere
Calling R the radius of the first sphere, the electric field just outide the surface of the first sphere is

The second sphere has a radius which is 3 times that of the smaller sphere:

So, the electric field just outside the second sphere is

So, the correct answer is 1/9.
Explanation:
700N right
to get the net force
you gotta let one direction be the negative ( the smaller force)
so the total force towards the left is 100N ( 60 + 40= 100)
which is smaller than the right force which is 800 N so you let 100 N be negative
so without even calculating , you can know that it will be moving towards the right because right force > left force
your add both forces ( remember 100 N is negative)
so 800N + ( - 100N)
= 700N
towards the right
hope this helps
this is just one method that helped me understand
please mark it brainliest