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icang [17]
3 years ago
9

Suppose that the carbon atom pictured here as a reactant had already formed a double bond with another carbon atom. how many hyd

rogen atoms would now be required to fill the carbons outer shell? bond formation between carbon and hydrogen to form methane. suppose that the carbon atom pictured here as a reactant had already formed a double bond with another carbon atom. how many hydrogen atoms would now be required to fill the carbons outer shell? bond formation between carbon and hydrogen to form methane. one two three four
Chemistry
2 answers:
prisoha [69]3 years ago
8 0

C has a valency of four. C can form 4 covalent bonds.  

The electron configuration of C:

1s²2s²2p²

When C already forms a double bond with another C atom, each of the two C atoms can form only 2 new covalent bonds. This is illustrated by the example below:

H₂C=CH₂

The molecule is an alkene called ethene.  

ivanzaharov [21]3 years ago
7 0
A carbon atom is capable of bonding with 4 atoms including carbon itself. So, when there is a double bond between two carbon atoms, each carbon atom has an extra 2 unoccupied bonds. <em>Thus, each carbon atom in a C=C bond is capable of bonding with two other hydrogen atoms.</em>
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A mixture of water and graphite is heated to 600 K in a 1 L container. When the system comes to equilibrium it contains 0.17 mol of H2, 0.17 mol of CO, 0.74 mol of H2O, and some graphite.

The equilibrium constant K_c=  \dfrac{[CO][H_2]}{[H_2O]}

The equilibrium constant  K_c=  \dfrac{(0.17 )(0.17)}{0.74}

The equilibrium constant K_c=  0.03905

Some O2 is added to the system and a spark is applied so that the H2 reacts completely with the O2.

The equation for the reaction is :

H_2 + \dfrac{1}{2}O_2 \to H_2O \\ \\ 0.17 \ \ \ \ \  \ \ \ \ \to0.17

Total mole of water now = 0.74+0.17

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0.03905 =  \dfrac{[0.17+x][x]}{[0.91 -x]}

0.03905(0.91 -x) = (0.17 +x)(x)

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0.0355355 +0.13095 x -x²

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By using quadratic formula

x = 0.265  or   x = -0.134

Going by the value with the positive integer; x = 0.265 moles

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= 0.17 + x

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= 0.435 moles

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