Question

What volume of 15.6M NH4OH is needed to make 500.0 mL of 3.00M solution? a) 0.962 L b) 0.00962 L c) 0.026 L d) 0.0962 L

Answer 1

Answer:

d) 0.0962 L

Explanation:

The problem describes a dilution process, meaning that we can solve it by using the following equation:

• C₁V₁=C₂V₂

Where subscript 1 stands for the volume and concentration of the concentrated solution, and 2 for those of the diluted solution. That means that in this case:

• C₁ = 15.6 M

• V₁ = ?

• C₂ = 3.00 M

• V₂ = 500 mL

We input the data:

• 15.6 M * V₁ = 3.00 M * 500 mL

And solve for V₁:

• V₁ = 96.2 mL

Finally we convert 96.2 mL to L:

• 96.2 mL / 1000 = 0.0962 L

The answer is thus option d).