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statuscvo [17]
3 years ago
6

HURRY IM TIMED ON THIS!!

Physics
1 answer:
sashaice [31]3 years ago
4 0

Answer:

The correct answer is A. increasing the positive charge of the positively charged object and increasing the negative charge of the negatively charged object

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What is the pH of a solution with a hydrogen ion concentration of 2.0x10^3.(Use 3 digits)
Luba_88 [7]

Answer:

2.70

Explanation:

pH = -log[H+]

pH = -log[2.0x10^-3]

pH = 2.70

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The wavelength on a longitude wave is
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The wavelength<span> in a </span>longitudinal wave<span> is probably the  distance between two consecutive compressions or between two consecutive rarefactions. The amplitude is the maximum displacement from equilibrium. ... The amplitude is the distance from the equilibrium position of the medium to a compression or a rarefaction.</span>
6 0
4 years ago
why does the number 54289.00 have seven significant figures and not five? explain using the rules of significant figures
SCORPION-xisa [38]

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7 0
3 years ago
Read 2 more answers
A capacitor that uses 0. 40- mmmm -thick paper as a dielectric is charged to the maximum sustainable voltage. What is the streng
Nonamiya [84]

The maxiumum strength of the induced electric field in the capacitor that uses thick paper as dielectric material is 16 x 10⁶ V/m.

<h3>What is maximum electric field strength?</h3>

The maximum electric field strength above which an insulating material begins to break down and conduct is called its dielectric strength.

The dielelectric strength of paper is given as;

E = 16 MV/m = 16 x 10⁶ V/m

Thus, the maxiumum strength of the induced electric field in the capacitor that uses thick paper as dielectric material is 16 x 10⁶ V/m.

Learn more about dielectric strength here: brainly.com/question/27017570?source=archive

#SPJ1

6 0
2 years ago
The 0.100 kg sphere in (Figure 1) is released from rest at the position shown in the sketch, with its center 0.400 m from the ce
slega [8]

Answer:

the speed of 0.10 sphere when it is moved to 0.20 kg  to the left is :   3.3337*10^{-5} \ m/s

Explanation:

Using the expression of the Change in  Gravitational Potential Energy:

U= -(\frac{ Gm_1m_2 }{r_2} - \frac{ Gm_1m_2 }{r_1}) \\ \\ U=Gm_1m_2 (\frac{ 1 }{r_2} - \frac{ 1 }{r_1})

So when the sphere exerts just 10 kg mass; the change in the gravitational potential energy is :

U_1=Gm_1m_2 (\frac{ 1 }{r_2} - \frac{ 1 }{r_1})

U_1=6.67*10^{-11}*0.1 \ kg*10 \ kg(\frac{ 1 }{0.6 \ m} - \frac{ 1 }{0.8 \ m})

U_1 = 2.778*10^{-11} J

the change in the gravitational potential energy  when the sphere exerts just 5 kg mass is ;

U_2=Gm_1m_2 (\frac{ 1 }{r_2} - \frac{ 1 }{r_1})

U_2=6.67*10^{-11}*0.1 \ kg*5 \ kg(\frac{ 1 }{0.4 \ m} - \frac{ 1 }{0.2 \ m})

U_2 = -8.335*10^{-11} J

The net total change is:

U_{total } = U_1 +U_2

U_{total} = 2.778*10^{-11} + (-8.335*10^{-11})

U_{total} = -5.557*10^{-11}

We all know that for there to be a balance ;loss of gravitational potential energy must be equal to the gain in kinetic energy .

SO;

K.E =  5.557*10^{-11}

\frac{1}{2}mv^2 = 5.557*10^{-11}

v^2 = \frac{2*5.557*10^{-11} \ J}{m_1}

v=\sqrt{ \frac{2*5.557*10^{-11} \ J}{0. 1 \kg}

v = 3.3337*10^{-5} \ m/s

Thus, the speed of 0.10 sphere when it is moved to 0.20 kg  to the left is :   3.3337*10^{-5} \ m/s

6 0
4 years ago
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