Answer:
1.85
Explanation: Estimate the total mass of a binary system is done by a reformulation of <em>Kepler's Third Law</em>, which states that the square of the period of a planet's orbit is proportional to the cube of its semimajor axis, i.e.:

where
a is semimajor axis in astronomical units (AU);
P is period measured in years;
is total mass of the two-stars system;
For the two stars faraway in the Milky Way:
1 year is equivalent of 365 days, so period in years:

P = 1.63 years
Calculating total mass:



1.85
<u>The total mass of the two-object system is 1.85 mass units.</u>
Answer:
1 / f = 1 / o + 1 / i
1 / image distance + 1 / object distance = 1 focal length
If the object distance is large the image will be at about the focal length
The value of 1 / f is fixed for any one particular lense
As the object distance decreases the image must increase
The above equation can also be written as
o i / (i + o) = f or i / (i / o + 1) = f
If for instance o was very large the image would be at the focal length
Answer: Electromagnetic radiation
Explanation:
Electromagnetic radiation is a combination of oscillating electric and magnetic fields, which propagate through space carrying energy from one place to another.
To understand it better:
This radiation is spread thanks to the electromagnetic fields produced by moving electric charges and their sources can be natural or man-made.
It should be noted that the energy of electromagnetic radiation can vary and depending on its frequency it can be useful for various situations.
<u>Answer</u>
46,200 J
The energy of given out when a substance is losing heat is given by:
H = mcΔθ
Where m is the mass of the substance,
c is the specific heat capacity of the substance and
Δθ is the temperature change.
H = 0.50 × 22 4200
= 46,200 Joules.
Answer:


Explanation:
Given:
temperature of source reservoir, 
temperature of sink reservoir, 
energy absorbed from the source, 
work done, 
a.
<u>Now change in entropy of the surrounding:</u>

<em>Since heat engine is a device that absorbs heat from a high temperature reservoir and does some work giving out heat in the universe as the byproduct.</em>



b.
<u>We know Carnot efficiency is given as:</u>



<u>Now the Carnot work done:</u>


.......................(1)
c.
From eq. (1) we have the Carnot work, so the difference:



Now, we find:
