Answer:
1. True WA > WB > WC
Explanation:
In this exercise they give work for several different configurations and ask that we show the relationship between them, the best way to do this is to calculate each work separately.
A) Work is the product of force by distance and the cosine of the angle between them
WA = W h cos 0
WA = mg h
B) On a ramp without rubbing
Sin30 = h / L
L = h / sin 30
WB = F d cos θ
WB = F L cos 30
WB = mf (h / sin30) cos 30
WB = mg h ctan 30
C) Ramp with rubbing
W sin 30 - fr = ma
N- Wcos30 = 0
W sin 30 - μ W cos 30 = ma
F = W (sin30 - μ cos30)
WC = mg (sin30 - μ cos30) h / sin30
Wc = mg (1 - μ ctan30) h
When we review the affirmation it is the work where there is rubbing is the smallest and the work where it comes in free fall at the maximum
Let's review the claims
1. True The work of gravity is the greatest and the work where there is friction is the least
2 False. The job where there is friction is the least
3 False work with rubbing is the least
4 False work with rubbing is the least
Answer:
(A) 60 J
Explanation:
At state 1
KE₁=100 J
At state 2
KE₂ = 0
U₂=80 J
Given that surface is rough so friction force will act in opposite to the direction of motion
Lets take work done by friction = Wfr
From work power energy
Work done by all forces = Change in kinetic energy
Wfr + U₂=ΔKE
Wfr+80 = 100
Wfr= 20 J
Now when book slides from top position then
Wfr+ U = KEf - KEi
-20 + 80 = KEf-0
KEf= 60 J
(A) 60 J
1 Kilojoule [kJ] = 737.562 149 277 27 Foot pound force [ftlbf]
Answer:
Option C. Both technicians A and B are correct
Explanation:
Vehicle-to-vehicle communications consists of a wireless network where automobiles send messages containing operational information such as speed, location, direction of travel, braking, and loss of stability.
Technician A is correct, there will be fewer traffic collision because each driver will have enough information about traffic flow and such information will be properly managed since they have been known before hand.
By letting out information, such as your location, direction of traffic, etc, there is loss of privacy. This can lead to a security threat on the part of the users
Answer:
Producing 300 L of ethanol from potatoes
Explanation:
From the diagram, one liter of ethanol production from sugar cane requires 2000 liters of water. Hence, in order to produce 100 L of ethanol from sugar cane, 2000 x 100 = 200,000 L of water.
1000 liters of water is needed to produce 1 liter of ethanol from sugar beet. Hence, 200 x 1000 = 200,000 L of water will be needed to produce 200 liters of ethanol.
1000 liters of water is also required to produce 1 liter of ethanol from potatoes, hence, 300 x 1000 = 300,000 L of water would be required to produce 300 L of ethanol from the same material
About 500 liters of water is required to produce 1 liter of ethanol from corn, hence, 400 x 500 = 200,000 L of water would be needed to produce 400 L of ethanol from corn.
<u>In conclusion, producing 300 L of ethanol from potatoes would require using the most water among all the options.</u>
