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Digiron [165]
3 years ago
11

The orbits of asteroids are found primarily between

Chemistry
1 answer:
ANEK [815]3 years ago
4 0
Im not sure i understand your question butttt there is an asteroid feild in between the planets mars and jupiter
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A person suffering from hyponatremia has a sodium ion concentration in the blood of 0.116 M and a total blood volume of 4.7 L .
klemol [59]

Explanation:

Normal moles of Na^{+} = volume × normal concentration

                              = 4.7 × 0.139 = 0.6533 mol

Moles of Na^{+} in hyponatremia blood = volume × hyponatremia concentration

                              = 4.7 × 0.116 = 0.5452 mol

Moles of NaCl to be added = moles of extra Na^{+} needed

                            = 0.6533 mol - 0.5452 mol = 0.1081 mol

Mass of NaCl = moles × molar mass of NaCl

                        = 0.1081 mol × 58.443

                        = 6.317g

                        = 6.32 g (approx)

Thus, we can conclude that mass of sodium chloride would need to be added to the blood is 6.32 g.                    

3 0
3 years ago
A balloon is filled with 0.250 mole of air at 35°C. If the volume of the balloon is 6.23 liters, what is the absolute pressure o
Jobisdone [24]
X= 101.325 kPa
The absolute pressure of the air in the balloon is 101.325 kilopascals.
6 0
3 years ago
Hecking skills activated
artcher [175]

Answer:

yes 34

Explanation:

4/13 =0.307

7 0
2 years ago
Read 2 more answers
A hot lump of 30.5 g of iron at an initial temperature of 52.7 °C is placed in 50.0 mL H2O initially at 25.0 °C and allowed to r
slava [35]

Answer:

26.7°C

Explanation:

Using the formula; Q = m × c × ΔT

Where; Q = amount of heat

m = mass

c = specific heat

ΔT = change in temperature

In this question involving iron placed into water, the Qwater = Qiron

For water; m= 50g, c = 4.18 J/g°C, Initial temp= 25°C, final temp=?

For iron; m = 30.5g, c = 0.449J/g°C, Initial temp= 52.7°C, final temp=?

Qwater = -(Qiron)

m × c × ΔT (water) =- {m × c × ΔT (iron)}

50 × 4.18 × (T - 25) = - {30.5 × 0.449 × (T - 52.7)}

209 (T - 25) = - {13.6945 (T - 52.7)}

209T - 5225 = -13.6945T + 721.7

209T + 13.6945T = 5225 + 721.7

222.6945T = 5946.7

T = 5946.7/222.6945

T = 26.7

Hence, the final temperature of water and iron is 26.7°C

8 0
3 years ago
if the half-life of substance A is 1.5 years, how long would it take a 8.0 gram sample of substance A to decay such that only 1.
Fudgin [204]

Answer:

4.5

Explanation:

3 0
3 years ago
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