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2 years ago

- 7th Grade Work - Please help, I really need it T-T

Mathematics

2 answers:

Lesechka [4]2 years ago

8 0

Answer: the first side is x the next side is x-5 the third side is 2x the fourth side is 4(2x) the fifth side is 4(2x)-2

a possible perimeter for the figure would be 113

Step-by-step explanation: if the first side was 6 -5 is 1+6 is 7+6*2 is 19+4(6*2)=67 67+ 4(6*2)-2 is 11

Vsevolod [243]2 years ago

5 0

Answer: the first side is x the next side is x-5 the third side is 2x the fourth side is 4(2x) the fifth side is 4(2x)-2

a possible perimeter for the figure would be 113

Step-by-step explanation: if the first side was 6 -5 is 1+6 is 7+6*2 is 19+4(6*2)=67 67+ 4(6*2)-2 is 113

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Maple grove wants to include two types of maple trees, the namesake of the city, for their parks. Two varieties of maple trees h

klasskru [66]

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3 years ago

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If f(x)= 5x + 4 and g(x) = 1/2x<br><br> find ,<br> a) fg(5)

Veseljchak [2.6K]

Answer:

f(g(5)) = 16.5

Step-by-step explanation:

To calculate f(g(5)), evaluate g(5) then substitute the value obtained into f(x)

g(5) = $\frac{1}{2}$ × 5 = 2.5 , then

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3 years ago

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Write and solve a system of equations for the situation described below. Define your variables and write your solution as a sent

Delicious77 [7]

N = nickels and q = quarters

0.05n + 0.25q = 1.90
n = 2q + 3

0.05(2q + 3) + 0.25q = 1.90
0.10q + 0.15 + 0.25q = 1.90
0.10q + 0.25q = 1.90 - 0.15
0.35q = 1.75
q = 1.75/0.35
q = 5 ......there are 5 quarters

n = 2q + 3
n = 2(5) + 3
n = 10 + 3
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6 0

3 years ago

The perimeter of a rectangle is 400 feet and the length of the rectangle is 3 times the width. find the dimensions of the rectan

bazaltina [42]

Width: x
Length: 3x
Perimeter=x+x+3x+3x=8x
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Dimension is 150×50 feet (length × width)

8 0

3 years ago

2. Given a quadrilateral with vertices (−1, 3), (1, 5), (5, 1), and (3,−1):

zlopas [31]

<h2>Explanation:</h2>

In every rectangle, the two diagonals have the same length. If a quadrilateral's diagonals have the same length, that doesn't mean it has to be a rectangle, but if a parallelogram's diagonals have the same length, then it's definitely a rectangle.

So first of all, let's prove this is a parallelogram. The basic definition of a parallelogram is that it is a quadrilateral where both pairs of opposite sides are parallel.

So let's name the vertices as:

$A(-1,3) \\ \\ B(1,5) \\ \\ C(5,1) \\ \\ D(3,-1)$

First pair of opposite sides:

<u>Slope:</u>

$\text{For AB}: \\ \\ m=\frac{5-3}{1-(-1)}=1 \\ \\ \\ \text{For CD}: \\ \\ m=\frac{1-(-1)}{5-3}=1 \\ \\ \\ \text{So AB and CD are parallel}$

Second pair of opposite sides:

<u>Slope:</u>

$\text{For BC}: \\ \\ m=\frac{1-5}{5-1}=-1 \\ \\ \\ \text{For AD}: \\ \\ m=\frac{-1-3}{3-(-1)}=-1 \\ \\ \\ \text{So BC and AD are parallel}$

So in fact this is a parallelogram. The other thing we need to prove is that the diagonals measure the same. Using distance formula:

$d=\sqrt{(y_{2}-y_{1})^2+(x_{2}-x_{1})^2} \\ \\ \\ Diagonal \ BD: \\ \\ d=\sqrt{(5-(-1))^2+(1-3)^2}=2\sqrt{10} \\ \\ \\ Diagonal \ AC: \\ \\ d=\sqrt{(3-1)^2+(-5-1)^2}=2\sqrt{10} \\ \\ \\$

So the diagonals measure the same, therefore this is a rectangle.

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3 years ago