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bekas [8.4K]
3 years ago
11

A particular substance has a measured solubility in water of 3.6 g/1.0 L. How much of the substance can be dissolved in 650 L of

water?
Chemistry
1 answer:
bonufazy [111]3 years ago
4 0

Answer : 2.34 kg or 2340 g can be dissolved in the given amount of water

The solubility of the substance is given as 3.6 g/1.0 L. That means 3.6 grams of the substance can be dissolved in 1 L of water.

We have 650 L of water. The equation can be set up as follows.

650 L \times \frac{3.6g}{1.0 L}= 2340 g

We can cancel out L here

Therefore we can say that 2340 grams or 2.34 kg of the substance can be dissolved in the given amount of water

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A student has two unopened 33 CL cans containing carbonated water. Can A has been stored in the garage 32 degrees and can B has
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Answer:

A. Can A will make a louder and stronger fizz than can B.  

Explanation:

The solubility of a gas in a liquid decreases as the temperature increases, so the warmer can will have more undissolved carbon dioxide.

The warmer can will be under greater pressure, so it will make a louder and stronger fizz.

7 0
3 years ago
In an acid-base titration,
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Answer:

b

Explanation:

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3 years ago
Use the periodic table to determine the electron configuration for iodine (i). express your answer in condensed form.
Dovator [93]
Iodine electron configuration is:

1S^2 2S^2 2P^6 3S^2 3P^6 4S^2 3d^10 4P^6 5S^2 4d^10  5P^5
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So we can write the electron configuration of Iodine:
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8 0
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The reaction of Pb+4 and O-2 produces the compound of
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Answer:

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Explanation:

The given species are:

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Now, to solve this problem, we use the combining powers which corresponds to the number of electrons usually lost or gained or shared by atoms during the course of a chemical combination.

                                          Pb⁴⁺               O²⁻  

Combining power               4                    2

Exchange of valencies        2                    4

Now the molecular formula is  Pb₂O₄

                               

4 0
2 years ago
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