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bekas [8.4K]
3 years ago
11

A particular substance has a measured solubility in water of 3.6 g/1.0 L. How much of the substance can be dissolved in 650 L of

water?
Chemistry
1 answer:
bonufazy [111]3 years ago
4 0

Answer : 2.34 kg or 2340 g can be dissolved in the given amount of water

The solubility of the substance is given as 3.6 g/1.0 L. That means 3.6 grams of the substance can be dissolved in 1 L of water.

We have 650 L of water. The equation can be set up as follows.

650 L \times \frac{3.6g}{1.0 L}= 2340 g

We can cancel out L here

Therefore we can say that 2340 grams or 2.34 kg of the substance can be dissolved in the given amount of water

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15 grams of sodium reacts with a certain amount of chlorine to yield 37 grams of sodium chloride, as shown below.
ale4655 [162]

Answer: 22g of chlorine would be needed to carry out this synthesis reaction

Explanation:

A synthesis reaction is one in which two or more than two elements combine together to forma single product.

Na+Cl\rightarrow NaCl

The atoms present in the reactants are found on the product side. According to the law of conservation of mass, the number of atoms on both sides of the arrow must be same as the total mass must be conserved.

15 grams of sodium reacts with 22 grams of chlorine to yield 37 grams of sodium chloride. Thus 22g of chlorine would be needed to carry out this synthesis reaction.

4 0
3 years ago
The forensic technician at a crime scene has just prepared a luminol stock solution by adding 13.0 g of luminol into a total vol
Andrews [41]

Answer:

0.978 M

Explanation:

Given data

  • Mass of luminol (solute): 13.0 g
  • Volume of the solution = volume of water: 75.0 mL = 0.0750 L

We can find the molarity of the stock solution of luminol using the following expression.

M = mass of solute / molar mass of solute × liters of solution

M = 13.0 g / 177.16 g/mol × 0.0750 L

M = 0.978 M

3 0
3 years ago
Acids will corrode most _____.<br> bases<br> liquids<br> metals<br> gases
aliya0001 [1]
Acids corrode most metals
3 0
3 years ago
Read 2 more answers
If 30 ml of water containing 15 mg of salicylate is extracted with 30 ml of chloroform, 2.59 mg of salicylate remains in the wat
In-s [12.5K]

Answer:

Distribution coefficient: 4.79

Explanation:

Distribution coefficient is the ratio between equilibrium concentration of non-aqueous phase and aqueous phase where both solvents are inmiscible. The equation for the problem is:

Distribution coefficient: Concentration in chloroform / Concentration in Water

<em>Concentration in water: 2.59mg / 30mL = 0.08633mg/mL</em>

<em>Concentration in chloroform: (15mg-2.59mg) / 30mL = 0.4137mg/mL</em>

<em />

Distribution coefficient: 0.4137mg/mL / 0.08633mg/mL

<h3>Distribution coefficient: 4.79</h3>
8 0
2 years ago
Determine the pressure in atm exerted by 1 mole of methane placed into a bulb with a volume of 244.6 mL at 25°C. Carry out two c
Nuetrik [128]

The pressure in atm exerted by 1 mole of methane placed into a bulb with a volume of 244.6 mL at 25°C is 101.94atm.

<h3>How to calculate pressure?</h3>

The pressure of an ideal gas can be calculated using the following formula:

PV = nRT

Where;

  • P = pressure
  • V = volume
  • n = number of moles
  • R = gas law constant
  • T = temperature

According to information in this question;

  • T = 25°C = 25 + 273 = 298K
  • V = 244.6mL = 0.24L
  • R = 0.0821 Latm/Kmol

P × 0.24 = 1 × 0.0821 × 298

0.24P = 24.47

P = 24.47/0.24

P = 101.94atm

Therefore, the pressure in atm exerted by 1 mole of methane placed into a bulb with a volume of 244.6 mL at 25°C is 101.94atm.

Learn more about pressure at: brainly.com/question/11464844

3 0
2 years ago
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