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Zinaida [17]
4 years ago
7

When a molecule absorbs an infrared photon it contributes to the ________energy of that molecule.

Physics
1 answer:
Tpy6a [65]4 years ago
5 0

Answer: INFRARED ENERGY

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Communication can be both verbal and nonverbal. <br><br> Question 2 options:<br> True<br> False
mafiozo [28]

Answer:

True

Explanation:

Verbal communication involves use of words to convey message and nonverbal communication involves use of sign language, body gestures etc to convey message

6 0
3 years ago
Aplicar ley de Seno y Coseno
ycow [4]

Answer:

Es 100000

Explanation: qppp-100

7 0
3 years ago
I have to submit my homework soon and I am not familiar with these concepts. can anybody do then for me?
AlladinOne [14]

#4).  The concepts are:  A). acceleration is always in the direction of the force, and B). friction always acts in the direction opposite to motion.  (that's B)

#5).  The concepts are:  A). the NET force is the sum of all the individual forces acting (on this car, it's 1600N forward).  and B). Force = (mass) x (acceleration).  So Acceleration = (force) / (mass).  For this car, that's (1600N forward) / (800 kg) .

#6).  The concept is:  As long as you don't exceed the "proportionality limit" of a spring, its extension is proportional to the load on it.  That means that the change in extension is always proportional to the change in the load.  So now, look at the table:  As long as the load is 10N or less, the spring stretched 3cm longer for every 2N more of load.  But if the load is somewhere between 10N and 12N, that relationship disappears.  Something changes between 10N and 12N of load.  The spring's "elastic limit" is somewhere in that slot.


6 0
3 years ago
2.5kg of water (C = 4189 J/(Kg x K)) is heated from T1 = 13.5 C to T2 = 22.5 C
kondor19780726 [428]

Answer:

338 K

Explanation:

m_{1} = 2.5 kg, c = 4189 J/(kg K), T_{1} = 13.5 ^{o} C, T_{2} = 22.5 ^{o} C

m_{2} = 0.5 kg, T_{3} = 20 ^{o} C

Heat loss by hotter water = heat gained by cooler water

m_{1}cΔT = m_{2}cΔT

m_{1}c(T_{2} - T_{1}) = m_{2}c(T_{4} - T_{3})

2.5 x 4189 x (22.5 - 13.5) = 0.5 x 4189 x (T_{4} - 20)

2.5 x 4189 x 9 = 2094.5 (T_{4} - 20)

94252.5 = 2094.5T_{4} - 41890

94252.5 + 41890 = 2094.5T_{4}

136142.5 = 2094.5T_{4}

T_{4} = \frac{136142.5}{2094.5}

    = 65

T_{4}  = 65 ^{o} C

But,

θ K = 273 + θ^{o} C

      = 273 + 65

      = 338

The final temperature of the water is 338 K.

3 0
3 years ago
A 3.00 kg cart on a frictionless track is pulled by a string so that it accelerates at 2.00 m/s/s. what is the tension in the st
lys-0071 [83]
The mass is m =  3kg

The acceleration is a =  2m/s/s

Force is equal to mass times acceleration

F = m*a = 3kg*2m/s/s = 6 N

This force is equal to the tension in the string

T = 6 N
3 0
4 years ago
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