Answer:
is the total displacement (volume) of the submarine.
Explanation:
Mass of water carried by submarine at 1000 ft depth = m = 2100 kg
The density of seawater at 1000 ft depth = d = ![1033 kg/m^3](https://tex.z-dn.net/?f=1033%20kg%2Fm%5E3)
Volume of the water displaced = V= ?
Total displacement of the submarine = Volume of the water displaced = V
![Density=\frac{Mass}{Volume}](https://tex.z-dn.net/?f=Density%3D%5Cfrac%7BMass%7D%7BVolume%7D)
![V=\frac{m}{d}=\frac{2100 kg}{1033 kg/m^3}=2.023 m^3](https://tex.z-dn.net/?f=V%3D%5Cfrac%7Bm%7D%7Bd%7D%3D%5Cfrac%7B2100%20kg%7D%7B1033%20kg%2Fm%5E3%7D%3D2.023%20m%5E3)
is the total displacement (volume) of the submarine.
The order of the answers are as follows:
B
C
D
A